# A homework in Direct Circuit for beginning students

#### fdbjruitoirew

1. Homework Statement

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2. Homework Equations

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3. The Attempt at a Solution

Well, I am not familiar with the Latex system on this website, just because I am a newbie and I rarely access to this forum. I have a problem (may be simple for you guys) but I still need a solution from you, or at least, please give me the answer if you are boring with typing a lot of formulae.

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#### fdbjruitoirew

Thanks naspook
I did have the solution that was solved by myself, and I think it's suitable for pupils, not a student but one day, my little brother gave a solution that was different to mine, and he believes that my solution is not right, So I need an answer from you to check.

#### nsaspook

So I need an answer from you to check.
Why don't you give your answer and the steps you took to find your results first in the proper format for this forum.

#### phinds

Gold Member
You need to read the forum rules. We help folks figure out how to solve problems, we do NOT just "give answers".

#### fdbjruitoirew

Why don't you give your answer and the steps you took to find your results first in the proper format for this forum.
Yeah, my steps: this DC circuit is a familiar one and we only need to know that with the given assumption as the ammeter is ideal, the potential difference between two points of $\ R_5$ is zero, then as a consequence $\ {I_5}=0A$. And $\ {I_1}=2A$, $\ {I_2}=2A$,$\ {I_3}={I_4}=1A$, then from Kirchooff law, $\ {I_A}=4A$.
Net resistance of the circuit is $\ {R_{AB}}=6Ω$

#### BvU

Homework Helper
Yeah, well, you sure take big steps. Especially from I5 to I1, 2,3,4. Perhaps you want to explain the 2,2,1,1 in a little more detail ? And: what did your young brother find ?

#### fdbjruitoirew

to BvU:
Well, this problem can be solved simply by re-draw the circuit with the rule as: Consider all points that have the equal potential is one. So we can have a new and simple diagram, from it we get I1, I2, I3, I4, and of course, I5=0 as mentioned above. It's my steps

My little brother: I think he did make a small fault when he re-draw the diagram

#### BvU

Homework Helper
Still: what did your young brother find ?

I agree with I5. Also with the two 1. But don't you become suspicious at all when 30 V over 6 Ohm gives 4 A ?

#### nsaspook

Yeah, my steps: this DC circuit is a familiar one and we only need to know that with the given assumption as the ammeter is ideal, the potential difference between two points of $\ R_5$ is zero, then as a consequence $\ {I_5}=0A$. And $\ {I_1}=2A$, $\ {I_2}=2A$,$\ {I_3}={I_4}=1A$, then from Kirchooff law, $\ {I_A}=4A$.
Net resistance of the circuit is $\ {R_{AB}}=6Ω$
Points for trying but you need to review a few things. It's aways good to work backwards (what voltage is across each node with your current calculations) from your result to check for errors.
http://www.usna.edu/Users/cs/vincent/suppnotes/EE301Topic06.pdf [Broken]

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#### fdbjruitoirew

Of course, nasaspook, we should review it, but I did knew this theory many years ago when I was in 9-grade class and I did give my answer.
Could anyone give me your numerical answer, that is all I need

#### fdbjruitoirew

Could anyone give the answer for me? I need it to check, this problem seems to be simple, but I need the answer from you

#### BvU

Homework Helper
Could anyone give me your numerical answer, that is all I need
Is not the way PF works. You have a choice to ignore answers to questions and hints to improve your work. You can not ask for 'the answer'.

"A homework in Direct Circuit for beginning students"

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