A left Artinian ring that is also a right Noetherian ring

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1. Prove that a ring which is left Artinian and right Noetherian is right Artinian.



The Attempt at a Solution



I can't figure it out. Can anyone help?
 
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What are the definitions of these terms?
 
A left Artinian ring R is a ring for which every descending chain R=I0 ⊃I1 ⊃I2 ⊃…⊃In ⊃… of its left ideals stabilizes, i.e. there is a k such that In+1 =In for all n≥k

A right Noetherian ring R is ring in which every ascending chain of right ideals stabalizes
 
So if a ring is left Artinian and right Noetherian, what can you say? What would you like to have happen to conclude that this ring is also right Artinian?
 
When you post a question here, include information like what you have below in your initial post. That's why the 2nd section on relevant equations and definitions is there in the template. It should just be erased.
frankusho said:
A left Artinian ring R is a ring for which every descending chain R=I0 ⊃I1 ⊃I2 ⊃…⊃In ⊃… of its left ideals stabilizes, i.e. there is a k such that In+1 =In for all n≥k

A right Noetherian ring R is ring in which every ascending chain of right ideals stabalizes
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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