A little electronics question about logical gates

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The discussion centers on understanding logical gates, specifically OR and AND gates, and their simplification using Boolean algebra. Participants clarify the definitions of logical addition, multiplication, and negation, emphasizing the importance of truth tables for beginners. Errors in truth tables are identified, particularly regarding the outputs of AND and OR operations, with corrections provided through examples. The conversation also touches on De Morgan's Laws and the simplification of expressions, leading to a final output that is dependent on the inputs. The thread concludes with a collaborative effort to ensure accurate understanding and application of Boolean algebra principles.
  • #31


Femme_physics said:
Isn't that the definition of ##\overline { \overline{ab}c }## ?

Errr... no?
Why would you think so?
 
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  • #32


Femme_physics said:
Isn't that the definition of ##\overline { \overline{ab}c }## ?

No you can't write it like that but you can use de morgan law to solve that:

\overline{\overline{ab}c}

\overline{\overline{ab}} + \overline{c}

ab + \overline{c}

But using: \overline{ab} = \overline{a} + \overline{b}
 
  • #33
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  • #34


Looks like you got the hang of boolean algebra! :approve:

However, you dropped something when you had ##\overline{cc}## and went to ##cc##.EDIT: I missed the abc part which is not right. Fixed it in post #38.
 
Last edited:
  • #35


I like Serena said:
Looks like you got the hang of boolean algebra! :approve:

However, you dropped something when you had ##\overline{cc}## and went to ##cc##.

True, but at the end of the day the result is still 0 cause we got a and a(capped) in the same multiplication line so everything gets nullified, right?
 
  • #36


Femme_physics said:
True, but at the end of the day the result is still 0 cause we got a and a(capped) in the same multiplication line so everything gets nullified, right?

Actually, you don't have ##\overline{a}##, but you have ##\overline{ab}##.
But yes, in combination with ##ab##, everything gets nullified.
 
  • #37


I like Serena said:
Actually, you don't have ##\overline{a}##, but you have ##\overline{ab}##.
But yes, in combination with ##ab##, everything gets nullified.

Ah, gotcha! Now I am asked to write the logical value of the function Out, when the values of all the ports
C = '0'
A = B = '1'

But still, everything gets nullified right?
 
  • #38


Hold on, I missed something.

It does not get nullified.

You got ##\overline{\overline{ab}c}##, which you took to ##abc##, but that is not right.
That changes everything.
 
Last edited:
  • #41


Could you add parentheses in the 3rd line?
 

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