A metal rod and a metal ball more submerged in H2O

AI Thread Summary
The discussion focuses on calculating the acceleration of a metal ball submerged in water when the temperature of the water is increased from 30 K to 65 K. Given the volumes and specific heat capacities of both the metal rod and ball, along with their masses, the problem involves understanding hydrostatic principles and thermal expansion. The initial length of the rod is 6 m, and the final calculated acceleration of the ball is 1.8 x 10^10. Participants emphasize the importance of thermal properties and hydrostatic forces in the calculation. The problem illustrates the interplay between temperature changes and the resulting physical effects on submerged objects.
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A metal rod and a metal ball more submerged in h2o, such that one end of the rod is adjacent to the ball. if the h2o will be heated from 30 k to 65 k, what is the acceleration of the ball? the initial length of the rod is 6 m.

Vball= 6 cm3
Vrod= 9 cm3
Crod= 13 cal/g.c degrees
Cball= 8 cal/g.c degrees
Ch2o= 1.0 cal/g.c degrees
Mball= 60 g
Mrod= 607 g
α= 0.005/c degrees

Topic is about Hydrostatic

I was absent during the assigning of this homework. I really need help! Thank you! :)
 
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Answer is 1.8 x 10^10
 

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