A passenger rushing to catch a plane at the airport

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To determine how long it takes for the passenger to cross the 110 m moving sidewalk, the combined speed of the passenger and the sidewalk must be calculated, resulting in a total speed of 4.5 km/h (3.0 km/h + 1.5 km/h). Converting this speed to meters per second gives approximately 1.25 m/s. Dividing the total distance of 110 m by this speed results in a time of 88 seconds to reach the other end of the sidewalk. The distance the passenger walks relative to the sidewalk can be calculated by considering the time spent walking at 3.0 km/h, which translates to approximately 73.33 meters. Understanding the relationship between walking speed and distance is crucial for solving these types of problems.
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could anyone help me with this problem and just explain how to find the answer? Thanks


A passenger rushing to catch a plane at the airport walks on a moving sidewalk at a speed of 3.0 km/h relative to the sidewalk in the direction that the sidewalk is moving. The sidewalk is 110 m long and moves with a steady velocity of 1.5 km/h. How long (in s) does it take for the passenger to get from one end of the sidewalk to the other, that i *to cover the 110 m?


Through what distance does the passenger walk relative to the moving sidewalk? This is the question I am having trouble with
 
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no in relation to the ground
 
It's a ratio between his walking speed on the sidewalk and off it in relation to the ground. The distance he walks is proportional to the speed he walks (for the same amount of steps). Understand?
 

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