Solving for Time in Uniform Circular Motion and Moving Sidewalk Problems

  • Thread starter Thread starter shade585
  • Start date Start date
  • Tags Tags
    Couple
Click For Summary

Homework Help Overview

The discussion involves two distinct problems: one related to uniform circular motion and centripetal acceleration, and the other concerning the dynamics of a moving sidewalk in an airport terminal. The first problem focuses on calculating specific values related to acceleration and velocity in circular motion, while the second problem explores the time taken by a person walking on a moving sidewalk compared to another person walking without it.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of centripetal acceleration and the dot product of acceleration and velocity in the first problem, with some expressing uncertainty about the next steps. In the second problem, participants explore the relationship between distance, time, and velocity, questioning how to eliminate distance from their equations.

Discussion Status

Some participants have provided guidance on the mathematical relationships involved, particularly in the second problem, where a participant suggests combining velocities into a single equation. There is an acknowledgment of the need to solve for time in the context of the moving sidewalk problem, with some participants expressing clarity after receiving assistance.

Contextual Notes

Participants note that the problems involve specific time constraints and assumptions about the velocities of individuals involved. The first problem's parameters are defined by the given period and radius, while the second problem assumes equal walking speeds for Larry and Moe.

shade585
Messages
13
Reaction score
0

Homework Statement



A centripetal-acceleration addict rides in uniform circular motion with period T = 3.58 s and radius r = 3.00 m. At one instant his acceleration is a = (7.00 m/s2)i + (-6.00 m/s2)j. At that instant, what are the following values?

I found r x a to be 0 m^2/s^2 which is right. I cannot figure out v dot a.

Homework Equations



I used the Period equation to get a velocity of 5.27 m/s.

The Attempt at a Solution



From here I do not know what to do.


Homework Statement



The airport terminal has a moving sidewalk to speed passengers through a long corridor. Larry does not use the moving sidewalk. He takes 185 s to walk through the corridor. Curly, who simply stands on the moving sidewalk, covers the same distance in 108 s. Moe boards the sidewalk and walks along it. How long does Moe take to move through the corridor? Assume that Larry and Moe walk at the same speed.

Homework Equations



I know the distance to be the same. I know i have two velocities. One is the velocity at which Larry and Moe walk. The other is the velocity of the sidewalk. I set up the distance to be a ratio of the distance over the time it took to go the length of the sidewalk. I cannot figure out how to make d cancel out. I know that i need to find an algebraic equation that will do so. I think i just need a nudge in the right direction.
 
Physics news on Phys.org
shade585 said:

Homework Statement



A centripetal-acceleration addict rides in uniform circular motion with period T = 3.58 s and radius r = 3.00 m. At one instant his acceleration is a = (7.00 m/s2)i + (-6.00 m/s2)j. At that instant, what are the following values?

I found r x a to be 0 m^2/s^2 which is right. I cannot figure out v dot a.

Homework Equations



I used the Period equation to get a velocity of 5.27 m/s.

The Attempt at a Solution



From here I do not know what to do.


Homework Statement



The airport terminal has a moving sidewalk to speed passengers through a long corridor. Larry does not use the moving sidewalk. He takes 185 s to walk through the corridor. Curly, who simply stands on the moving sidewalk, covers the same distance in 108 s. Moe boards the sidewalk and walks along it. How long does Moe take to move through the corridor? Assume that Larry and Moe walk at the same speed.

Homework Equations



I know the distance to be the same. I know i have two velocities. One is the velocity at which Larry and Moe walk. The other is the velocity of the sidewalk. I set up the distance to be a ratio of the distance over the time it took to go the length of the sidewalk. I cannot figure out how to make d cancel out. I know that i need to find an algebraic equation that will do so. I think i just need a nudge in the right direction.


What is the formula of centripetal acceleration?
 
a = v^2/r
 
shade585 said:
a = v^2/r

Oh sorry.You are just told to find out a dot b.So in that case angle between a and v is 90 and hence a dot b is 0. I hope that i have not misunderstood your question.
 
Oh ok. I see it now. Thanks for the help.
 
As for the second question, suppose that the length of the sidewalk is d m. Then Larry's velocity is v_L = d / 185 m/s and the velocity of the sidewalk is v_S = d / 108 m/s.
Now what is Moe's velocity? Once you have the velocity, how can you find the time it takes him to walk d m?

Now tell us: is the problem in writing down this equation or in solving it?
 
i had the two velocities. Moe's velocity should be d/185 m/s + d/108 m/s. The equation I can think of is d = (d/185 m/s + d/108 m/s)t.
 
That's correct, so the problem is in solving for t.
You have an equation of the form
d = \left( \frac{d}{a} + \frac{d}{b} \right) t.
Try writing the bracketed term in one fraction,
\frac{d}{a} + \frac{d}{b} = \frac{db}{ab} + \frac{da}{ab} = \frac{d(a + b)}{a b}.
Now can you solve it?
 
yes thank you. it seems so obvious now. I got 68 seconds.
 
  • #10
I got that too (actually, 68 \frac{56}{293}), but usually an error of one significant digit is allowed (technically speaking, all numbers in the question are given in three significant digits, so if you want to write your answer decimally you would write it with the same precision, e.g. 68,2 s)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
11K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
885
Replies
2
Views
10K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K