A perturbation operator problem

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SUMMARY

The discussion centers on the perturbation operator problem in quantum mechanics, specifically evaluating the integral <2s|V|2p,m=0>. The formula v=ezE is confirmed as correct, with the result of the integral likely being 3eaE. The context provided indicates that the 2s and 2p orbitals are degenerate hydrogen atom orbitals, which is crucial for understanding the evaluation process.

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einstein1921
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hi,my friends.I have a perturbation operator problem.
v=ezE;
why this formula is right?how to deduce it?a is bohr radius.
thank you!
 

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You could add more context to your question.
<2s|V|2p,m=0> can be evaluated if you know how the orbitals look like. It is an integral which (probably) gives the result 3eaE.
 
mfb said:
You could add more context to your question.
<2s|V|2p,m=0> can be evaluated if you know how the orbitals look like. It is an integral which (probably) gives the result 3eaE.

thank you!2s 2p orbital is the hydrogen atom orbital ,they are degenerate.
thank you again!
 

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