A position versus time graph involving the unit circle

AI Thread Summary
The discussion focuses on the misunderstanding of the relationship between amplitude and wavelength in the context of a position versus time graph. Participants clarify that the amplitude of an oscillation is not the same as wavelength and emphasize the importance of correctly identifying the amplitude from the graph. The original equation presented is deemed incorrect, and the need for a proper equation related to simple harmonic motion (SHM) is highlighted. Suggestions are made to consult notes or textbooks for accurate information. Overall, the conversation stresses the necessity of understanding fundamental concepts in wave mechanics.
littlejon
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Homework Statement

Homework Equations


v(x)t= -wAsin(w+o)

The Attempt at a Solution


-5(10)sin(0)= 0
D
is this the right procedure?
 
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littlejon said:
v(x)t= -wAsin(w+o)
I'm not aware of any such equation. The equation you want is of the form x(t) = .
littlejon said:
is this the right procedure?
No.
The first step is to figure out the amplitude. Can you think how to read that off the graph?
 
amplitude is 5
 
littlejon said:
amplitude is 5
No. How did you arrive at that? How is the amplitude of an oscillation defined?
Have you found a correct equation?
 
I just saw the wavelength and assumed it was 5.
 
littlejon said:
v(x)t= -wAsin(w+o)
This equation is wrong.
 
littlejon said:
I just saw the wavelength and assumed it was 5.
Amplitude is not wavelength. What do you think is meant by the amplitude of a wave?
You still haven't provided any correct equations related to SHM. Don't you have any notes or textbooks? If not, read it up online.
 

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