A Question about an unbiased estimator

  • Thread starter Thread starter Artusartos
  • Start date Start date
Artusartos
Messages
236
Reaction score
0

Homework Statement



The random sample X_1, ... , X_n has a N(0, \theta) distribution. So now I have to solve for c such that Y= c \sum^n_{i=1} is an unbiased estimator for \sqrt{\theta}.

Homework Equations


The Attempt at a Solution



E(c \sum^n_{i=1} |X_i|) = c \sum^n_{i=1} E(|X_i|) = c \sum^n_{i=1} \int \frac{|X_i|}{\sqrt{2(\pi)(\theta)}}e^{-X_i/(2\theta)}

So now I have to solve...

c \sum^n_{i=1} \int \frac{|X_i|}{\sqrt{2(\pi)(\theta)}} e^{-X_i/(2\theta)} = \sqrt(\theta), right? But how can I integrate the absolute value of X_i?

Thanks in advance
 
Last edited:
Physics news on Phys.org
Split the range of integration into x < 0, x > 0.
The random sample X1,...,Xn has a N(0,θ) distribution.
Do you mean, X1,...,Xn are independent samples from a N(0,θ) distribution? If so, why the subscript on θi?
 
haruspex said:
Split the range of integration into x < 0, x > 0.

Do you mean, X1,...,Xn are independent samples from a N(0,θ) distribution? If so, why the subscript on θi?

Oh sorry, it's supposed to be just \theta
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top