A question about conservation of momentum

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The discussion centers on the conservation of momentum in a scenario where frogs jump from a boat. When all frogs jump simultaneously, the boat experiences a velocity v1 in the opposite direction, while jumping sequentially results in a greater velocity v2 for the boat. The difference arises from the timing of the impulses; simultaneous jumps create a larger force over a shorter time, while sequential jumps apply smaller forces over a longer duration. The velocities v, v1, and v2 are defined relative to the boat and the water, leading to confusion about their reference points. Understanding these dynamics clarifies why the boat's velocity differs based on the timing of the frogs' jumps.
papercace
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Let's say you've got a boat filled with n frogs of mass m each. Let's also say that all the frogs jump simultaneously out of the boat in the same direction with velocity v, then the boat will get a velocity v1 in the opposite direction because of conservation of momentum.

Now if we instead let each frog jump separately with velocity v, the boat will get a velocity v2 that is bigger than v1.

I did see the formula and the derivation for why the boat gets a different velocity, but I'm still not getting it intuitively. If the same mass is leaving the boat at the same velocity, why does the boats velocity differ depending upon when the mass leaves the boat?
 
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papercace said:
Let's say you've got a boat filled with n frogs of mass m each. Let's also say that all the frogs jump simultaneously out of the boat in the same direction with velocity v, then the boat will get a velocity v1 in the opposite direction because of conservation of momentum.

Now if we instead let each frog jump separately with velocity v, the boat will get a velocity v2 that is bigger than v1.

I did see the formula and the derivation for why the boat gets a different velocity, but I'm still not getting it intuitively. If the same mass is leaving the boat at the same velocity, why does the boats velocity differ depending upon when the mass leaves the boat?

What happens if all the frogs do an identical jump (it terms of the mechanics of their jump)?
 
papercace said:
If the same mass is leaving the boat at the same velocity, why does the boats velocity differ...
Those two velocities are relative to what?
 
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Buzz Bloom said:
Hi papercace:

Perhaps the following will be helpful.

Regard,
Buzz

Yes I know what impulse is. If the frogs jump simultaneously, then the impulse time will be short but the force impacted on the boat will be large. If they jump one after the other, the force of each jump will be small but they will do it over a longer time. In the end they should add up to be the same impulse, I think.

PeroK said:
What happens if all the frogs do an identical jump (it terms of the mechanics of their jump)?

Sorry I don't understand your question.

A.T. said:
Those two velocities are relative to what?

Yeah I should have stated that. v is relative to the boat while v1 and v2 are relative to the water.
 
papercace said:
Yeah I should have stated that. v is relative to the boat while v1 and v2 are relative to the water.
So what is the velocity of the frogs with respect to the water in the two cases?
 
papercace said:
Yeah I should have stated that. v is relative to the boat while v1 and v2 are relative to the water.
That still leaves v ambiguous -- relative to the boat pre-leap, post-leap or mid-leap?
 
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