Artusartos
- 236
- 0
Homework Statement
For question 19.2 in this link:
http://people.ischool.berkeley.edu/~johnsonb/Welcome_files/104/104hw7sum06.pdf
I came up with a different proof, but I'm not sure if it is correct...
Homework Equations
The Attempt at a Solution
Let |x-y|< \delta
For |f(x)-f(y)| = |x^2 - x^y| = |x-y||x+y| < \delta|x+y|, we know that the largest that |x+y| can be is 6. So if we let \delta= \epsilon/6...
We will have
|f(x)-f(y)| = |x^2 - x^y| = |x-y||x+y| < \delta|x+y| < (\epsilon/6)(6) = \epsilon
If this is true for the largest possibility, then it must be possible for all of them...
Do you think my answer is correct, or is there something that I'm missing?
Thanks in advance
Last edited by a moderator: