What is the Asymptotic Behavior of the Propagator in QFT?

[ndung200790]

Please demonstrate for me that:
In any theory,the propagator \Delta_{f}(k) of a field of type f has asymptotic behavior:

\Delta_{f}(k)~k^{-2+2sf}

where sf is ''spin'' of the field.For massive fields of Lorentz type (A,B) then sf=A+B.
(However,dropping terms that because of gauge invariance have no effect,eg. photon has sf=0)
(QFT of Weinberg Vol 1,&12.1 Degrees of Divergence)

 

[ndung200790]

I know this is true for photon,W-Z boson,gluon,graviton,spin 1/2 fermion.But what about the other particles?