- #1

Dangshnizzle

- 7

- 0

**The problem statement:**

A square centered at the origin has its vertices on the x- & y- axes.

The graph of the function f(x)=ax

^{2}-4 , a>0

Passes through three of the square's vertices.

You must find what 'a' makes this statement true.

**Other things to know:**

Well I think there are multiple solutions to the problem. But I only need one. It would really help if you could show work and explain how you got your answer.

Thanks in advance to anyone who assists.

__Solved:__f(x)=(0.25)X

^{2}-4

'a'=0.25

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