- #1
Dangshnizzle
- 7
- 0
The problem statement:
A square centered at the origin has its vertices on the x- & y- axes.
The graph of the function f(x)=ax2-4 , a>0
Passes through three of the square's vertices.
You must find what 'a' makes this statement true.
Other things to know:
Well I think there are multiple solutions to the problem. But I only need one. It would really help if you could show work and explain how you got your answer.
Thanks in advance to anyone who assists.
Solved:
f(x)=(0.25)X2-4
'a'=0.25
A square centered at the origin has its vertices on the x- & y- axes.
The graph of the function f(x)=ax2-4 , a>0
Passes through three of the square's vertices.
You must find what 'a' makes this statement true.
Other things to know:
Well I think there are multiple solutions to the problem. But I only need one. It would really help if you could show work and explain how you got your answer.
Thanks in advance to anyone who assists.
Solved:
f(x)=(0.25)X2-4
'a'=0.25
Last edited: