A Series of Even numbers squared

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SUMMARY

The discussion centers on deriving a general formula for the sum of the squares of even numbers up to a given even number N, expressed as 2^2 + 4^2 + 6^2 + ... + N^2. The relevant equation for the sum of squares is provided: \(\sum r^2\) from r=1 to r=N equals \(\frac{1}{6} n(n+1)(2n+1)\). By factoring out 2^2 from the series, the problem simplifies to calculating the sum of squares of the first N/2 integers, leading to a clearer path for deriving the formula.

PREREQUISITES
  • Understanding of summation notation and series
  • Familiarity with the formula for the sum of squares
  • Basic algebraic manipulation skills
  • Knowledge of even and odd number properties
NEXT STEPS
  • Study the derivation of the sum of squares formula \(\sum r^2\)
  • Explore the implications of factoring in algebraic expressions
  • Learn about series convergence and divergence
  • Investigate other series summation techniques, such as arithmetic series
USEFUL FOR

Students studying mathematics, particularly those focusing on series and sequences, educators teaching algebra, and anyone interested in mathematical problem-solving techniques.

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Homework Statement



Is there a general formula for the sum of such a series (or can it be self derived) ?

2^2 + 4^2 + 6^2 + 8^2 ... N^2 (all the way till some even number N)

Homework Equations



[itex]\sum r^2[/itex] (from r=1 to r=N) = 1/6 * n(n+1)(2n+1)

The Attempt at a Solution



No clue where to start.
 
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Do all the terms have a common factor that you can pull out?
 
Oh... I did not see that. Great thinking !

After taking 2^2 common we will get a simple sequence :

1^2 + 2^2 + 3^2 + 4^2 ...

I think I get it !
 

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