A Solid Sphere Release From Rest at the top of a Ramp.

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SUMMARY

A 2.0 kg solid sphere with a radius of 0.10 m is released from rest at the top of a ramp that is 0.75 m high and 5.3 m long. The total kinetic energy (Ktotal) is calculated using the formula Ktotal = mgh, where m is the mass and h is the height. The rotational kinetic energy (Krot) and translational kinetic energy (Ktranslation) are derived from the ratio of moment of inertia, with Krot/Ktranslation = 2/5. The specific calculation shows that Ktranslation equals 5/7 mgh, confirming energy conservation during pure rolling motion.

PREREQUISITES
  • Understanding of gravitational potential energy (mgh)
  • Knowledge of kinetic energy formulas (Ktotal, Krot, Ktranslation)
  • Familiarity with the concept of moment of inertia
  • Basic principles of rolling motion and energy conservation
NEXT STEPS
  • Study the derivation of moment of inertia for different shapes
  • Learn about energy conservation in rolling motion
  • Explore the effects of friction in rolling without slipping
  • Investigate the relationship between linear and angular velocity in rolling objects
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of rolling motion and energy conservation principles.

aZenki
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Please help me with this question. Thank you.

A 2.0 kg solid sphere (radius = 0.10m) is released from rest at the top of a ramp and allow to roll without slipping. The ramp is 0.75m high and 5.3 m long. Find Ktotal, Krot, and Ktranslation.
 
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Pure rolling takes place, work done by friction is 0. Energy is conserved. Ktotal=mgh, Krot/Ktranslation=2/5 ie in ratio of moment of inertia. Ktranslation=5/7 mgh etc
 

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