solve the initial value problem: y''+8.4y'+17.64y=e-4.2x y(0)=1, y'(0)=1 y(x)=? The way I tried to achieve is to solve the corresponding homo equation first: y''+8.4y'+17.64y=0, which gives yc; yc=c1e-4.2x+c2e-4.2xx Then try to find yp, generally I would assume a yp=Ae-4.2x, but from the yc got above, clearly yp=Ae-4.2x or yp=Ae-4.2xx is not good. If I add one more 'x' in yp assumption,in which it seems A has to be 0, which is not right either.... Any idea? Or I made some mistake? Meric.