A triple integral involving deltas

Click For Summary
SUMMARY

The discussion focuses on evaluating a triple integral involving delta functions, specifically the integral of the expression (x^2 + 32*z^2) * cos(y) * e^(x - 4*z) multiplied by delta(x - 1), delta(y - pi), and delta(z - 0.25). The participant concluded that the integral evaluates to zero due to the properties of the delta function, which results in the overall multiplication yielding zero when evaluated at the specified points. The participant also clarified their understanding of the delta function's role in integrals, confirming that it simplifies the evaluation process by collapsing the integral to the function's value at the delta's argument.

PREREQUISITES
  • Understanding of triple integrals in calculus
  • Familiarity with the properties of the Dirac delta function
  • Knowledge of basic trigonometric functions and their integrals
  • Experience with exponential functions in mathematical expressions
NEXT STEPS
  • Study the properties of the Dirac delta function in more depth
  • Learn about evaluating multiple integrals in calculus
  • Explore applications of delta functions in physics and engineering
  • Investigate advanced topics in calculus, such as distributions and generalized functions
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with integrals and delta functions, particularly those seeking to deepen their understanding of advanced calculus concepts.

skrtic
Messages
14
Reaction score
0
SOLVED

Homework Statement


evaluate the intergral

Homework Equations

sorry about how this is going to look don't know the language to display nicely and wouldn't take my copy and pasteall integrals are form -infinity to infinity

(x^2+32*z^2)*cos(y)*e^(x-4*z) delta(x-1) delta (y-pi) delta(z-.25) dx, dy dz

The Attempt at a Solution

well i looked at just the cos(y) part and got sin(y) then for the delta i plugged in pi since it is zero elsewhere and that gives me a 0 overall and since it is all mulitplication that makes the whole integral o?

thats my take.

never really understood the delta's in integrals
 
Last edited:
Physics news on Phys.org
\int_{-\infty}^{+\infty}dx\,f(x)\delta(x-a) = f(a)
 
ok. that makes sense. and kinda looks familiar now that i see it and makes the problem a little better.

thanks
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
9K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
6
Views
2K