About transformersplease explainthanks

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Transformers operate with key concepts like kVA, input power, output power, and losses. kVA represents the apparent power, while the relationship between input and output power is influenced by the power factor. Copper losses increase with current, leading to higher losses at full load compared to half load, as power loss is proportional to the square of the current. When the load is halved, the output power also reduces significantly due to the relationship between current and power loss. Understanding these principles clarifies how transformers function and the impact of load on efficiency.
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I am learning about transformers, and I am really confused! Please explain what's kVA,input power,output power,and the copper losses and iron losses.can the kVA be taken as input power that's v1i1, how is kVA related to the input and output.is kVA into power factor equal to output. And how is copper power loss at full load is 4 tim es that of half load.how does the out put power become half when load is made half?? I am familiar with the basic stuff.its this kVA and load that has messed things up.
 
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Is v1i1 equals( kVA+ p(iron loss) + p(copper loss))
Expression correct? If yes how does the book say that v1i1 equals kVA equals V2i2??
:(
 
cartik said:
how is copper power loss at full load is 4 tim es that of half load.how does the out put power become half when load is made half??
The term "load" for a transformer being shorthand for secondary current, where full load means the full rated secondary current, and half load being half of this.

Code:
Copper losses in the model are represented by the current in a resistance,
it dissipates energy as heat. 

power loss = I².R

if you consider half current, then power loss 
= (½.I)².R
= ¼.I².R ... and there you see that factor of ¼
:smile:
 
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