AC circuit with dependant current and voltage source and open circuit element

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SUMMARY

The discussion focuses on solving an AC circuit problem involving dependent current and voltage sources, specifically finding Vx in terms of Ix. Participants suggest using mesh analysis and super node analysis, while emphasizing that the left loop can be ignored. The key takeaway is to express Vx as a function of Ix, with the equation derived from the current source in the circuit, leading to the expression Vx = 30 * Ix / 30.

PREREQUISITES
  • Understanding of mesh analysis in circuit theory
  • Familiarity with super node analysis techniques
  • Knowledge of dependent sources in AC circuits
  • Basic principles of Ohm's Law and circuit equations
NEXT STEPS
  • Study mesh analysis techniques in AC circuits
  • Learn about super node analysis and its applications
  • Explore dependent sources and their impact on circuit behavior
  • Practice deriving circuit equations from given parameters
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing AC circuits with dependent sources will benefit from this discussion.

Yarnzorrr
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I've been given the following problem (attached), not sure how to tackle this one, do I use mesh/node analysis and super node analysis, or can I find the v in the loop with the dependent voltage source then use that as the supply to the second and third loops?

Not sure, any help would be appreciated. Thanks!
 

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The problem asks you to find Vx in terms of Ix. Seems to me that you can ignore the left hand loop entirely for this and just assume that Ix is, well, Ix. So what current does the current source in the middle produce?
 
So I just find the current through the 2 and 1 KΩ on the left, ignoring the dependent voltage source?
 
Yarnzorrr said:
So I just find the current through the 2 and 1 KΩ on the left, ignoring the dependent voltage source?
No, you just ignore the left hand loop entirely. Ix is the given current; You're looking for an expression (equation), not a numerical result.
 
eg just look at the right hand side. Take the input as 30*Ix. Write the equation and divide by 30.
 

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