AC current measurement question

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The discussion centers on the challenges of measuring AC current in a firing circuit for oilfield perforating. The user is familiar with DC circuits but seeks clarification on wiring an AC ammeter in series, as is done with DC. It is noted that some AC ammeters have internal shunts, while others require external shunts to prevent damage. The user plans to research the specific meter model to understand its requirements better. Proper wiring and understanding of the meter's specifications are crucial for safe operation.
DXjohn
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Please excuse my rather dim question but I'm very familiar with homebrewing all manner of DC powered circuits but when it comes to AC..I'm in the dark, sorry.

I'm building a firing circuit for oilfield perforating. We will have AC (Generator) so I'm using a variac to slowly build-up voltage to fire the cap/pcord.
I have a AC voltmeter downstream of variac and have an AC ammeter but I've been told that you can't wire it in the circuit in series as you would in a DC circuit?
It is an old simpson panel meter and I'd like to wire it in but I don't want to fry it accidently.

My wiring sequence is:
AC>switch>variac>switch(safety)>voltmeter>cable to well

Does this make sense?
Thanks!
John
 
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DXjohn said:
have an AC ammeter but I've been told that you can't wire it in the circuit in series as you would in a DC circuit?
It depends on the meter. Some have an internal shunt and can be connected directly (in series of course), some require an external shunt. If yours requires the latter, it will indeed fry without it.

moo
 
moo said:
It depends on the meter. Some have an internal shunt ...

moo

Thanks moo,
I didn't know a shunt was applicable in AC current measurement.
I'll see if I can find a part # on meter and google some.
Thanks!
John
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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