hellfire said:
... an accelerated observer in a Minkowski spacetime, would be accelerated wrt to the virtual particles of the Minkowki vacuum. This means that the virtual particles would be accelerated with respect to him. The question is whether this charged virtual particles would radiate.
I believe I gave that answer in the last post; namely, a detector (or person) would see a
thermal radiation at a temperature given by the formula in my 1st post. [This is similar to thermal radiation discovered by Hawking (Hawking radiation) emitted by black holes, which result in their eventual evaporation.] Let me expand a bit.
Thermal radiation is simply photons that are a mix of frequencies near the thermal frequecy, w, which is strictly a function of temperature defined by:
w = KT
where T is Temp., and K = 3.67x10^11/sec.-*K
According to Unruh & Davies (see ref.#1), observers in an accelerating frame would see thermal radiation at a temperature given by the equation in my 1st post. This eqn. quantifies the fullness of the effect, (I've never heard of two effects). The distribution is apparently Planckian. The mechanism responsible for this radiation is basically that the quantum (zero point) vacuum fluctuations are being transformed into real photons by the acceleration.
However, if you solve for a (acceleration) in the former equation you will realize the extremely high accel. required to achieve any realistically measureable temperature, over 10^20 m/sec^2 or so. (Or conversely, g =9.8 m/sec^2 results in an infinitesmal 10^-20*K. temp.)
Creator
#1). P.C. Davies, J.Physics A, vol.8, p.609 (1975).
Also see W.G. Unruh, Phys. Rev.D, vol14.p.870, (1976).