Accelerating a micron size particle in an air stream

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In a 1m long, 10mm ID vertical tube with a known air flow rate, the velocity of micrometre-sized particles added to the air stream can be calculated using the Stokes drag law. The particle velocity approaches the air velocity over time, with the characteristic relaxation time determined by the particle size and air viscosity. For a 1 micron particle, the relaxation time is approximately 3 microseconds, indicating that the particle will reach the air velocity in this timeframe. The tube's length is sufficient for the particles to achieve this velocity before exiting. Understanding these dynamics is crucial for applications involving particle transport in air streams.
furrygerbil
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Hi,

I have a 1m long, 10mm ID vertical tube attached to a vacuum system. I have a known flow rate of the air down the tube which is used to calculate the air velocity.

My question is if I then add micrometre sized particles (initially at rest) to the air stream what is their velocity at the end of the tube?

I know that eventually the particles will reach the same velocity as the air stream they are suspended in but is the tube long enough to achieve this?

I have spent a long time googling various ideas about this and have drawn a blank on a simple solution and it might not even be possible (simply), so I hand the question over to the collective wisdom of Physics Forums :)

Kind Regards

Craig
 
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the particle velocity can be approximated by:
\frac{du_p}{dt}=\frac{1}{\tau_p}(u-u_p),
with u the air velocity and characteristic relaxation timescale is given by Stokes drag law:
\tau_p = \frac{\rho d_p^2}{18\mu}

if you have a 1 micron particle. the relaxation time is 3 microseconds, so you expect the particle to reach the air velocity in approximately this time.
 
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