Accelerating car, kinematics problem

AI Thread Summary
To solve the kinematics problem of a 2.3 x 10^3 kg car accelerating to +17 m/s in 21 seconds with a constant air resistance of -500 N, one should first identify the known variables: mass, initial and final velocities, time, and the opposing force. The average power developed by the engine can be calculated using the formula Power = Work / time, where Work is derived from Force multiplied by distance. Additionally, to find instantaneous power at t = 15 seconds, one must determine the force acting on the car at that moment, factoring in both the acceleration and air resistance. Understanding these relationships and equations is crucial for solving the problem effectively. The discussion emphasizes the importance of organizing knowns and unknowns to approach the calculations systematically.
Jessicaelleig
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A 2.3 103 kg car starts from rest and accelerates along a horizontal roadway to +17 m/s in 21 s. Assume that air resistance remains constant at -500 N during this time. Find
(a) the average power developed by the engine and

(b) the instantaneous power developed at t = 15 s.

I am really confused about this. If you can help, I would appreciate it. Thanks!
 
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Jessicaelleig said:
A 2.3 103 kg car starts from rest and accelerates along a horizontal roadway to +17 m/s in 21 s. Assume that air resistance remains constant at -500 N during this time. Find
(a) the average power developed by the engine and

(b) the instantaneous power developed at t = 15 s.

I am really confused about this. If you can help, I would appreciate it. Thanks!

I find a good place to start on any problem is to list the knowns and unknowns, then find equations that deal with those properties/units.

For instance, here you are given :
mass
initial velocity
final velocity
time
a force acting on the system

and you are looking for:
power

Keep in mind, power will have units in terms of Watts (or kW)
Power = Work / time
Work = Force * distance
Force = mass * acceleration


See if you can get started with that.
 
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