What is the vertical acceleration of the projectile?

[OblivionMage]

Homework Statement

Find the vertical acceleration of the projectile using the following points of data:

y-axis:

33.37
32.87
31.72
30.02
27.8
24.8
21.05
16.7
11.85
6.5
0.6

each value is 0.10s from each other in the x-axis (a mark is was made on the plot every 0.1s)

I know that the acceleration will slightly lower than -82cm/s/s

*all values in cm

Homework Equations

Vav=d/t

Trend line of a V/t graph should give the acceleration

The Attempt at a Solution

I tried to get the Vav of each segment:

1st)

the Vav between 33.37cm and 32.87cm = d/t:

d = 32.87cm - 33.37cm
d = -0.5cm

t = 0.1s - 0.0s
t = 0.1s

Vav = -0.5cm/0.1s
Vav = -5cm/s

2nd

the Vav between 32.87cm and 31.72 = d/t:

d = 31.72cm - 32.87cm
d = -1.15cm

t = 0.2s - 0.1s
t = 0.1s

Vav = -1.15cm/0.1s
Vav = -11.5cm/s

The full list of values:

-5
-11.5
-17
-22.2
-30
-37.5
-43.5
-48.5
-53.5
-59

*all values in cm/s

the trend line would be:

-32.77cm/s which would somehow equal the acceleration?

It makes sense that the values are accelerating downwards, but they are not doing so quickly enough (as stated above, the acceleration should be around (below) -82cm/s/s).

I'm unsure of what to do next, I know that my acceleration was not cm/s/s, but I'm not sure how I would get there.

Any help is appreciated ;)

 

[member 553083]

EDIT: (a) What is the total distance travelled?d = 33.37cm - 0.6cmd = 32.77cm(b) What is the time taken for the projectile to travel the 32.77cm?t = 32.77cm/Vavt = 32.77cm/-32.77cm/st = 1s