Acceleration Engineering First Semester

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germanmath
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Homework Statement
Acceleration
Relevant Equations
Engineering, biomedical, University
The function x (t) = 4 (m · s) t − 1 + 10 m describes the position of a mass point. In which direction does the speed point at time t = 1 s? Is the amount of speed constant or not? does the velocity function change its sign for t> 0 at some point? And in which direction does the acceleration point at time t = 1 s?

could someone help me please with Solving this task?
 
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Oh of course, I am sorry.

I would say that the mass point positions is in the height of 10m...
To get the speed I assume that I have to do the derivitation and then I have to calculate the speed for the value of t=1. is it right?
 
germanmath said:
Oh of course, I am sorry.

I would say that the mass point positions is in the height of 10m...
To get the speed I assume that I have to do the derivitation and then I have to calculate the speed for the value of t=1. is it right?
Is the formula supposed to be? $$x(t) = (4 m/s)(t-1s) + 10m$$ In any case, you get the velocity from the position by differentiation.
 
No, I am sorry I didnt noticed that it is incorrectly. The formula is supposed to be: x(t) =4(m*s)(t^-1) +10meter

okey thanks a lot for your answer :)