Acceleration in Two Dimensions of watercraft

AI Thread Summary
To determine the final velocity of a watercraft with an initial velocity of 6.4 m/s [E] and an average acceleration of 2.0 m/s² [S] over 2.5 seconds, the velocities should be separated into x (east) and y (south) components. The x component remains constant at 6.4 m/s, while the y component starts at 0 and increases due to the acceleration. The final velocity in the y direction can be calculated using the formula vfy = viy + ay * t, where viy is 0. The final velocities in both dimensions can then be combined using the Pythagorean theorem to find the resultant final velocity. This approach clarifies the necessary steps to solve the problem effectively.
chudzoik
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Homework Statement


A watercraft with an initial velocity of 6.4 m/s [E] undergoes an average acceleration of 2.0 m/s2 for 2.5 s. What is the final velocity of the watercraft?

Homework Equations


vf = vi + a * t
a = v / t
v = v2 + (-v1)
pythagoras and cosine law?

The Attempt at a Solution



I think I need to separate the velocities into x and y components and calculate the final velocity in both the x and y components to find the final velocity, but I don't know if that's correct. To be honest I don't really know where how to start the question.
 
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chudzoik said:
I think I need to separate the variables into x and y components and calculate the final velocity in both the x and y components to find the final velocity, but I don't know if that's correct.
Yep, that's how you should do it. You've got the x acceleration and y acceleration, and so you can solve the equations of motion for each coordinate separately.
 
But I don't think I have enough known variables to do that. If I use vfx = vix + ax * t then I don't have ax and I don't have the initial velocity in the y direction either so I can't figure out the final velocity in the y direction.
 
Yes, you do have ax, because the question says that the acceleration is only in the south direction.
And you do know the initial velocity in the y direction, because the question says that the initial velocity is purely to the east.
 
So they are both 0 then? I think that clears up a lot of my confusion with this problem.
 
Yep. that's right
 
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