Achromatism of Lenses: Answers to Your Questions

  • Thread starter Thread starter Amith2006
  • Start date Start date
  • Tags Tags
    Lenses
Click For Summary

Homework Help Overview

The discussion revolves around the achromatism of lenses, specifically focusing on the conditions required for forming achromatic combinations using lenses made of the same material. The original poster expresses confusion regarding the necessary configurations and properties of the lenses involved.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify the conditions for forming achromatic combinations, questioning whether one lens should be convex and the other concave, and exploring the implications of using lenses of the same material.
  • Participants raise questions about the dispersive powers of the lenses and the conditions under which achromatism can be achieved, including the necessity of different focal lengths and configurations.
  • Some participants suggest that the original poster should provide more background information and personal insights to facilitate better assistance.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the conditions for achromatism. Some guidance has been offered regarding the need for different indices of refraction and the role of dispersive powers, but no consensus has been reached on the correctness of the original poster's reasoning.

Contextual Notes

Participants note the lack of specific information about Abbe numbers in the original poster's textbook, which may be relevant to the discussion of achromatism. There are indications of time constraints affecting responses, and some participants express a willingness to wait for more informed contributions.

Amith2006
Messages
416
Reaction score
2

Homework Statement


I posted this question in Introductory physics section but no one is able to clear my doubt. That is why I have posted it here.Please guide me.
# I have some doubts regarding achromatism of lenses:

1)If we want to form an achromatic combination of lenses in which both are made of same material, one should be convex and the other should be concave, isn’t it? Is there any other condition to be satisfied along with this?
2)It is given in a book that, a convex achromatic combination of 2 lenses of the same material placed some suitable distance is possible in the following cases:
a)Both are convex
b)Both cannot be concave
c)Convex lens of greater focal length and concave lens of smaller focal length.
Is it true?

3)A convex achromatic combination of 2 lenses of the same material placed in contact can be obtained using a convex lens of lower dispersive power and a concave lens of higher dispersive power. Is it true?



Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
One of the reasons that you are not getting any help is that you have not shown any of your own work. What do you know about lenses? What do you know about how chromatic aberration is corrected? What is your textbook? What web resources have you tried? Have you read the wikipedia entry on chromatic aberration?

http://en.wikipedia.org/wiki/Achromat
 
Amith2006 said:

Homework Statement


1)If we want to form an achromatic combination of lenses in which both are made of same material, one should be convex and the other should be concave, isn’t it? Is there any other condition to be satisfied along with this?


For the first question,I think the reason behind having one convex and other concave in order to form an achromatic doublet is that, they disperse the beam in opposite directions as one is converging and other is diverging. According to the condition for achromatism of lenses,
w1/w2 = -f1/f2
as w1 & w2 are different, f1 & f2 should be different. Is it right?

For the second question,
a) If both are made of same material, then their dispersive powers will be same. From the condition for achromatism of lenses,
f1=-f2
If both are convex, then this is not possible, isn't it?
b) Similarly both cannot be concave.
c) Similarly this cannot be true.
So for achromatism of 2 lenses made of same material placed in contact:
# one should be convex and other should be concave.
# Both should be of same focal length.

3) I think the third question is wrong because 2 lenses made of same material cannot have different dispersive powers. Please correct me if I am wrong.
 
Last edited:
Now what is the reason for not responding?
 
Amith2006 said:
Now what is the reason for not responding?

Time constraints (work is extremely busy for me at the moment), and the fact that I'm not enough of an optics specialist to know the answers off the top of my head. I'd need to read the wiki article and spend some time thinking about it. What are the fundamental requirements to make an achromat? I would think it would take at least two different indices of refraction for a 2-element achromat, but I'm not sure without doing more reading.
 
If that is the case, I am prepared to wait. Thanks in advance.
 
Amith2006 said:
If that is the case, I am prepared to wait. Thanks in advance.

You shouldn't be waiting on me, Amith, or even waiting for another reply. Achromats are pretty straightforward. What have you learned about them from the wikipedia article and from your textbook?
 
berkeman said:
You shouldn't be waiting on me, Amith, or even waiting for another reply. Achromats are pretty straightforward. What have you learned about them from the wikipedia article and from your textbook?

Would you telling whether I am right or not?
 
Your answers look okay to me, but again I'm no optics expert. Does your text mention the Abbe numbers that the wikipedia article uses in the achromat calculations?
 
  • #10
There is nothing given about abbe numbers in my optics book. In fact I came to know about abbe numbers from Wikipedia. Could anyone good in optics tell whether my resoning is right or not?
 
  • #11
Bump!
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K