Adding Multiples of 2π to arctan(stuff) Answers: Is This Correct?

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Adding any integer multiple of π to the result of arctan(stuff) yields equivalent answers, as the tangent function is periodic with a period of π. Therefore, if arctan(stuff) equals a certain angle, adding multiples of 2π to that angle will still result in valid answers. This means that while the angles differ, they all correspond to the same tangent value. Consequently, it is correct to state that arctan(stuff) can have multiple equivalent angles by adding 2π. Understanding this periodicity is essential for working with trigonometric functions.
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I feel kind of dumb asking this (it's been a while sense I took precalc) but I always thought that if I had something like

arctan(stuff) = answer
that if I added any whole integer multiple of 2pi to the answer I would get equivalent answers. Is this correct? Like
answer - 4pi = answer -2pi = answer + 2pi = answer + 4 pi

you get different angles but they can still act as correct answers to
arctan(stuff)?
 
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GreenPrint said:
I feel kind of dumb asking this (it's been a while sense I took precalc) but I always thought that if I had something like

arctan(stuff) = answer
that if I added any whole integer multiple of 2pi to the answer I would get equivalent answers. Is this correct? Like
answer - 4pi = answer -2pi = answer + 2pi = answer + 4 pi

you get different angles but they can still act as correct answers to
arctan(stuff)?
tan(x) is periodic with a period of π .

So if you have arctan(stuff) = answer , then adding any integer multiple of π to 'answer,' will give 'another answer'.

In other words, if tan('answer') = stuff, then it's also true that tan('another answer') = stuff .
 
ok well in this case i can add multiples of two pi's as well than?
 
GreenPrint said:
ok well in this case i can add multiples of two pi's as well than?
Sure, since 2π is an integer multiple of π .
 
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