Displacement & Pythagorean Theorem: Triangle ABC

AI Thread Summary
The discussion centers on the relationship between displacement and the Pythagorean theorem in the context of vector addition. It clarifies that while the Pythagorean theorem applies to orthogonal vectors, the law of cosines is necessary for general vectors. The conversation distinguishes between measuring distance and displacement, noting that displacement is a specific type of vector quantity. Total distance is calculated as the sum of the magnitudes of the individual vectors, while total displacement is represented by the resultant vector. The dialogue highlights the ambiguity in definitions of "Euclidean vectors" among different fields, emphasizing the need for clarity in understanding vector concepts.
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Alright, we have triangle abc with hypotenuse c. So, if you add vector a and vector b, the answer is vector c.

Now, according to the pythagorean theorem, this would not make sense. But the pythagorean theorem is DISTANCE. I am guessing that this phenomenon has something to do with using displacement?
 
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Note, that the pythagorean theorem corresponds to the particular geometric situation where vector a and b are orthogonal on each other and in this case, the pythogorean theorem relates the length of the three vectors. For general vectors a and b, you need the law of cosine that includes the angle between a and b in order to related the length of a and b with the length of c.
 
My book says vector a + vector b = vector c. It uses (x,y) coordinates.

Vector a: (x1,y1)
Vector b: (x2,y2)
Vector c: (x1+x2, y1+y2)

Filip Larsen, what you just described gives me the magnitude of the displacement.

Am I measuring distance or displacement? Is the vector all about displacement?
 
Displacement is only one example of a vector quantity. It's the first one that most physics textbooks introduce. There are many others: velocity, acceleration, force, momentum, angular momentum, electric field, magnetic field, ...

In your example, the total distance traveled would be the sum of the lengths (magnitudes) of the displacement vectors a and b:

d_{total} = \sqrt{x_1^2 + y_1^2} + \sqrt{x_2^2 + y_2^2}

The total displacement would be simply the vector c, which has magnitude

\sqrt{(x_1 + x_2)^2 + (y_1 + y_2)^2}

and a direction (angle) given by

\tan \theta = \frac{y_1 + y_2}{x_1 + x_2}
 
What do you mean by "Euclidean vectors"?
 
Naty1's link is for Euclidean Vectors
 
Oh, silly me :wink: should've clicked on that.

From what I read in the article, it seems like a displacement vector is just one example of a Euclidean vector. Although it kind of depends on how you define "Euclidean vector" - there's a bit of ambiguity in the article, probably because different groups of people (e.g. physicists vs. mathematicians) have different definitions for the term.
 
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