Adiabatic heat exchanger problem

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SUMMARY

The discussion centers on solving an adiabatic heat exchanger problem involving propane gas and superheated steam. Propane enters at 40 degrees C and 250 kPa, exiting at 240 degrees C, while steam enters at 300 degrees C and 5.0 bar, exiting as a saturated liquid. Key equations for heat transfer include Q = m * Cp * ΔT and the use of steam tables to find specific enthalpy values. The discussion emphasizes the importance of heat balances and the Joules-Thompson effect in determining mass flow rates and energy transfer rates.

PREREQUISITES
  • Understanding of adiabatic processes in thermodynamics
  • Familiarity with steam tables for superheated steam
  • Knowledge of heat transfer equations, specifically Q = m * Cp * ΔT
  • Basic concepts of specific enthalpy and energy balance
NEXT STEPS
  • Study the use of steam tables for calculating enthalpy changes in steam
  • Learn about the Joules-Thompson effect and its implications in heat exchangers
  • Explore advanced heat exchanger design principles and calculations
  • Investigate the application of energy balance equations in thermodynamic systems
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Students and professionals in chemical engineering, mechanical engineering, and thermodynamics, particularly those working with heat exchangers and energy transfer systems.

marialo
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Adiabatic heat exchanger problem... Please Help!

I have this proplem as a homework assignment and I'm a bit stuck as houw to set it up. Here it is:

Propane gas enters a continuous adiabatic heat exchanger at 40 degrees C and 250 kPa and exits at 240 degrees C. Superheated steam at 300 degrees C and 5.0 bar enters the exchanger flowing countercurrent,y to the propane and exits as a saturated liquid at the same pressure.

I know how to draw the process flowchart, but the problem also asks to include in the labeling the mass of the steam fed (kg). I have no idea how to figure this out. Is it in some table, or chart?

Please Help, 'cause i am stumped!

-Thanks in advance...
 
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Adiabatic heat exchanger

Couple of questions for you: Do you own a copy of the si steam tables? Are you familiar with heat balances?

Ok, i will try and point you in the right direction .

Q= Of the steam = Q of the water

Thus Q=McpDT m= mass of water/steam Kg Cp=Specific heat Dt= (Outlet Temp - Inlet)

So call steam 1 and Water 2

M1*cP*DT1=M2*cp*DT2

OR we can say that Q=m*Hf-Hg and take the data from the steam tables for steam as we know the conditions in and out! once we know Q ofcourse...lol ( H is Empalthy)

Good luck , hope this is some help...half asleep so probs wrote crap! lol :smile:
 
i didn't mean water i meant propane...lol
 
The problem seems to relate to the Joules-Thompson effect...
 
"adiabatic heat exchanger" implies the heat is transferred from the hot fluid to the cold fluid. The change in energy of the hot fluid = change in energy of the cold fluid, or rather rate of energy transfer from the hot fluid = rate of energy transfer to the cold fluid.

\dot{m_h}\,c_p_h\,\Delta{T_h} = \dot{m_c}\,c_p_c\,\Delta{T_c} where h and c are hot and cold, \dot{m} is mass flow rate, cp is specific heat and \Delta{T} is the change in temperature. Or instead of c_p\,\DeltaT, one could use the change in specific enthalphy directly, which one can find in a thermodynamic table as a funtion of temperature and pressure for the given fluid.
 
Thats what i said...lol, but in laymen terms! :P
 

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