(adsbygoogle = window.adsbygoogle || []).push({}); 1. Propane vapour (1kmol) at a pressure of 40 bar and 230 C expands adiabatically to 0.25 bar and 95 C. Determine a)W, b)Delta S, c)The ammount of work obtained if the expansion were done reversibly from the same initial conditions to the final pressure of 0.25bar

2. I am not sure how to calculate work for a irreversible process. Is it zero, a gas that expands adiabatically in an irreversible process loses no kinetic energy right? so then work has to be zero cause heat is zero as well right? Im not sure about delta S either, I think in reversible delta S is zero but in irreversible its always increasing? I think theres is a formula for delta S for ideal This stuff can get confusing, can anyone help me?

3. The attempt at a solution

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# Adiabatic, Ideal gas, changing heat capacity, work calculation

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