Adiabatic, isothermal, or isovolumetric

AI Thread Summary
The thermodynamic process described involves adding 300 calories of heat to a gas, resulting in a 500-calorie increase in internal energy. The discussion centers on whether this process is isothermal, isovolumetric, or adiabatic. It is concluded that the process cannot be isothermal because an increase in internal energy typically indicates a change in temperature. The presence of work done on the gas suggests that the correct classification is not straightforward, leading to the possibility that the answer could be "none" of the given options. Ultimately, the increase in internal energy indicates that work is contributing to the energy change beyond just heat input.
c4iscool
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Here's my problem:

300 calories of heat are added to a gas as the internal energy of the gas increases by 500 calories. The described thermodynamic process is best described as?

My guess is that the process is isothermal b/c work is being done in the system.
 
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Since temperature is usually the measure of internal energy, it's unlikely that the internal energy increased without the temperature being changed. So that's probably not an isothermal process.
 
if that's the case then maybe it's isovolumetric b/c adiabatic can't have heat flow into or out of the system. any other ideas?
 
c4iscool said:
Here's my problem:

300 calories of heat are added to a gas as the internal energy of the gas increases by 500 calories. The described thermodynamic process is best described as?

My guess is that the process is isothermal b/c work is being done in the system.
In what form is the 200 calories of energy added to the gas (since it is not in the form of heat)? What does that tell you about what happens to the volume of the gas?

What makes you think this is a choice between adiabatic, isovolumetric and isothermal?

AM
 
It's a homework question and the answers are adiabatic, isovolumetric, isothermal or none. as for your other question about the other 200 calories, I have no clue. but I would think that the volume would stay the same. is that wrong?
 
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c4iscool said:
It's a homework question and the answers are adiabatic, isovolumetric, isothermal or none.
Then the correct answer is "None".

as for your other question about the other 200 calories, I have no clue. but I would think that the volume would stay the same. is that wrong?
As you observed, work is being done on the gas. That is what increases the internal energy of the gas over and above the heat that is added.

AM
 
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