Adjusting Telescoping Antenna Length

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Homework Help Overview

The problem involves determining the appropriate length for a telescoping antenna to optimize FM radio reception at a specific frequency of 100 MHz. The context is set around a vacation cabin located at the edge of the reception area.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss various equations found online for calculating antenna length based on frequency, including the formulas 143/frequency and 468/frequency. There is a question about the appropriate fraction of the wavelength to use for the antenna. Some participants express uncertainty about the units (meters vs. feet) and the implications of using different formulas.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to the problem. Some guidance has been offered regarding the relationship between antenna length and wavelength, as well as the importance of understanding the formulas being used. There is no explicit consensus yet on the correct approach.

Contextual Notes

Participants mention the need to clarify whether the answer should be in feet or meters, indicating potential confusion regarding units. There is also a reference to reviewing textbook material for better understanding.

Sevendust
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Homework Statement



"Your vacation cabin in the woods is at the very fringe of the reception area for the FM radio station in the previous question (that broadcasts at 100 mHz). In order to maximize your chances of receiving your favorite tunes clearly from this station, you should adjust the telescoping antenna of your portable radio to ____ meters in length."

Homework Equations



I missed class, so after some googling I found an equation online that stated that 143/frequency gives me the length in meters.

The Attempt at a Solution



143/100mhz = 1.43
I entered this and it was incorrect. Any help/equations I can use?
 
Last edited:
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Sevendust said:
googling I found an equation online that stated 468/frequency gives me the length in feet, and 143/frequency gives me the length in meters.

Hi Sevendust! http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Did you find what fraction λ is best for the whip antenna? Won't you need to know whether the answer should be in feet or metres, before entering it in an online quiz?

http://en.wikipedia.org/wiki/Whip_antenna
 
Last edited by a moderator:
Hey :), the answers going to be in metres, sorry if I made that vague in my first post. I'm not exactly sure what you mean by finding the fraction λ: can you explain?
 
fraction of λ = fraction of wavelength
 
You shouldn't use random formulas without understanding them. You should review your textbook before trying the problem.

The kind of antenna in question is usually 1/4 of the wavelength of the expected signal. You know the frequency, so you can calculate the wavelength. You may also need the rule of thumb that the electrical length of an antenna is about 95% of the physical length.
 
Got it: thanks for your help guys. I need to find a classmate with the notes so I can review for the test. Cheers.
 

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