Air Compression vs Water Depth

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SUMMARY

This discussion focuses on the relationship between air compression and water depth, specifically for a diving bell project using a 1-liter pickle jar. At a depth of 10 meters, the pressure doubles, resulting in the volume of air being halved, which means only 0.5 liters of usable space remains. The ideal gas law (pV=nRT) is referenced to explain the calculations involved. Participants emphasize the importance of understanding pressure dynamics and the effects of water pressure on the integrity of the glass jar.

PREREQUISITES
  • Understanding of the ideal gas law (pV=nRT)
  • Basic knowledge of pressure and buoyancy principles
  • Familiarity with the concept of atmospheric pressure changes with depth
  • Experience with basic physics related to fluid dynamics
NEXT STEPS
  • Research the effects of pressure on different materials, particularly glass, at varying depths
  • Learn about buoyancy and its impact on submerged objects
  • Explore practical applications of the ideal gas law in real-world scenarios
  • Investigate safety measures for underwater projects involving compressed air
USEFUL FOR

This discussion is beneficial for hobbyists building underwater devices, physics students seeking to understand pressure dynamics, and anyone interested in the practical applications of the ideal gas law in aquatic environments.

TjFitz
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Hey ya,

Well, I have been having a difficult time finding the answer to this question, probably because I don't know the specific terminology. So here I am. I did not know exactly which forum category to put this in so...

I am building a small diving bell with a remote controlled camer inside. Nothing more than a hobby project..

The Bell is actually nothing more than a 1 liter Pickle Jar.

What I am wondering is, how much compression of air can I expect at let's say a max of 10 meter depth. meaning if I have 1 liter of air in the jar, how far will that compress per meter fresh water depth.

I would like to know this because I need to know how much room in the jar I have that I can use, or even how deep I should limit myself before water would reach my gear in the jar.

is there a simple equation which states X cc/ml of air compression per meter depth?
 

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pV=nRT is all you need. Or even pV=const will do.

In general - look for ideal gas equation.

--
 


Borek
Thanks for your quick response... But what does it all mean...? I am basically an idiot in this :bugeye:
 
Yes, you can calculate exactly what the water pressure will be. If you are interested it is simple. If not, then you can use a diving rule of thumb of 1 atmosphere per every 10 meters of depth (it's within about .5 psi depending on a few things). At 10 meters you'll basically be doubling your pressure, therefore halving your volume which sounds like more than accurate enough for what you want to do.
 
sorry about my delayed responses, I believe there is an anti spammer thingy.. as a newbie my posts have to get approved first. all good..

SH. Ouch.. so, given the ballpark figure, I am filling half my jar at 10m.. looks like I am going to need a larger jar.. otherwise I am going to run out of useable dry space...
 
ok... one last question. (Promise I'll come back and show what I built)

Would the integrity of the glass (where the air is trapped) be acted upon in the same respect or would it only be effected by the same boyancy as when on the surface.. meaning, is the pressure of the water going to press on the glass or just where the water meets the air inside?

Oh.. and I Wiki'd the pV=nRT.. now it makes sense to me! Thanks B.
 
Pressure will be identical everywhere - which means you don't have to worry about it.

I feel like you will benefit from some reading about pressure and basic physics in general.
 
I do agree that I have a bit of reading to do. the only problem has been that most reading in physics as well as other scientific arenas, the authors asume you know so much already which I dont. I understand a lot and am quick to pick up things, I am often times at a loss for the starting info.. yaknow?

appreciate your help.
 

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