Air flow requirement of electrical enclosure

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SUMMARY

The discussion focuses on calculating the CFM (Cubic Feet per Minute) requirement for a fan in an electrical enclosure housing an inverter with a heat loss of 3000W. The enclosure is constructed from 2mm thick CRCA sheet and features fins for heat dissipation. The consensus is that accurate calculations should ideally be sourced from the inverter manufacturer or through specialized Mechanical Engineering (ME) and Chemical Engineering (ChemE) forums, as they possess the expertise in heat transfer calculations. For those pursuing self-calculation, resources such as the ASHRAE handbook and engineering heat transfer textbooks are recommended.

PREREQUISITES
  • Understanding of heat transfer principles
  • Familiarity with CFM calculations
  • Knowledge of materials used in electrical enclosures, specifically CRCA sheet
  • Basic concepts of forced air cooling systems
NEXT STEPS
  • Research the ASHRAE handbook for heat transfer formulae
  • Study engineering heat transfer textbooks for in-depth explanations
  • Explore inverter manufacturer specifications for cooling requirements
  • Engage with Mechanical Engineering forums for expert advice on heat dissipation
USEFUL FOR

Mechanical engineers, electrical engineers, HVAC professionals, and anyone involved in the design and cooling of electrical enclosures.

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I am putting one inverter in enclosure made out of CRCA sheet of 2mm thick. Enclosure has fins at the bottom side and at top hood. Inverter heat loss as per datasheet is 3000W. Can somebody help to calculate CFM requirement of fan for given allowed temperature-rise and heat transfer by conduction through enclosure body.
 
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Strictly this is more of a Mechanical Engineering question. Anything involving heat transfer is more frequented by MEs and ChemEs.

I've done these calculations before but they can get sufficiently involved that I'd probably never do them for free for anyone. You may want to try the ME or ChemE forums - these folks will be better at estimating off these kinds of things off the top of their heads than I or any EE can.

Honestly the easiest and most accurate answers will come from the manufacturer of the inverter and not a hand calculation by someone here. This is the kind of thing they should already have done, at least for still air rather than forced air cooling (the former is a more worst-case situation).

If you go it alone, I'd recommend a copy of the ASHRAE handbook for formulae and an engineering heat transfer textbook for explanations. All this is why I defer to my ME brethren (and sistern/cistern) when I can for heat transfer questions (my own or others').
 

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