Air resistance in relation to ballistics

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Discussion Overview

The discussion revolves around the effects of air resistance on the flight time and velocity of a bullet fired from a .50 caliber sniper rifle at a target two miles away. Participants explore the calculations involved in determining flight time, the impact of wind resistance, and the complexities of drag at supersonic speeds.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates that, neglecting air resistance, a bullet would take approximately 3.857 seconds to reach a target two miles away, based on initial velocity and acceleration due to gravity.
  • Another participant asserts that wind is not necessary to slow the bullet, as its motion through the air alone generates drag, described by a specific drag equation involving air density, velocity, cross-sectional area, and drag coefficient.
  • A third participant references a Mythbusters episode that found the terminal velocity of a bullet to be around 100 feet per second, suggesting that the drag required to explain a 5.5 second flight time would be excessively high.
  • Another participant notes that bullets from most rifles travel at supersonic speeds, complicating the drag calculations and requiring the use of tables of coefficients for accurate ballistics analysis.
  • This participant also questions the terminal velocity of a .50 caliber bullet, suggesting it would be significantly higher than 100 feet per second, contrary to the earlier claim regarding smaller calibers.

Areas of Agreement / Disagreement

Participants express differing views on the effects of air resistance and the calculations related to bullet flight time. There is no consensus on the impact of wind resistance or the accuracy of the terminal velocity figures mentioned.

Contextual Notes

The discussion includes assumptions about the neglect of air resistance in initial calculations and the complexity of drag calculations at supersonic speeds. Specific values for drag coefficients and terminal velocities are debated without resolution.

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Having this discussion on another board, basically stemmed from one member saying that a bullet would be in flight for "over 5 seconds"in response to something else someone said about a 0.50 caliber sniper rifle firing at a target 2 miles away.

I figured that negating air resistance, the time would be 3.857 seconds (using Vf^2 = Vi^2 + 2ad then putting finding average velocity (Vf + Vi)/2 and substituting that into v = d/t) "d" is two miles, or 10,560 feet, "Vi" is 2,800 feet per second, and "a" is -32.15 feet per second.

So assuming that was right, I found that for the time to be "over 5 seconds" (I used 5.5), the final velocity would have to be 1,040 feet per second (using v = d/t, solving for v as average velocity, multiplying Va by two and subtracting initial velocity to find the new Vf) is that correct?

Anyway, none of that really matters, just background, my question is, how do you take wind resistance into account in kinematics, and how high would the wind speed have to be to cause a 63% loss of velocity? I'd preferably like to do this without calculus.

Thanks in advance.
 
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Wind isn't needed to slow the bullet - just it's motion through the air is enough.
The force on an object moving through air (at height speed)
F = 1/2 \rho v 2 A C d

\rho is the density of air
v is the velocity
A is the cross section area
C d depends on the shape, for a bullet it's around 0.3
 
Mythbusters did a "can a falling bullet kill you" episode where they found the terminal velocity of a bullet to be around 100fps. You can plug that into the drag equation to find the drag coefficient (the bullet tumbled in their demo, but at least that gives you an upper bound). I think you'll find that the drag needed to explain the 5.5 second flight time is absurdly high.
 
Bullets from most rifles travel at super sonic speeds. At these speeds, the math to calculate the drag is so complex that tables of coefficients are required to do the ballistics calculations.

http://en.wikipedia.org/wiki/External_ballistics

In the case of 50 caliber sniper rifles, the muzzle velocity is very high, enough that the bullet will still be well above supersonic at impact to improve the accuracy.

russ_watters said:
Mythbusters did a "can a falling bullet kill you" episode where they found the terminal velocity of a bullet to be around 100fps.
Must have been a very small caliber weapon. Hunters sometimes get pelted by tiny birdshot falling from above without much harm, but people have died from falling bullets. I'm pretty sure that a 50 cailiber bullet would have a much higher terminal velocity than 100fps.
 
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