Airplane diving with a circle radius

AI Thread Summary
The discussion centers on calculating the magnitude of acceleration for a pilot pulling out of a dive in a circular arc with a radius of 320 m and a speed of 230 km/h. Participants clarify that the relevant acceleration is centripetal, calculated using the formula a = v²/r, where v is the velocity and r is the radius. There is confusion about the role of gravity and whether it should be included in the acceleration calculation. Ultimately, it is established that the pilot experiences centripetal acceleration, which can be determined independently of mass or gravitational effects. The focus remains on applying the correct formula to find the numerical value of the acceleration.
Robertoalva
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1. A 55 kg airplane pilot pulls out of a dive by following, at constant speed, the arc of a circle whose radius is 320 m. At the bottom of the circle, where her speed is 230 km/h, what is the magnitude of her acceleration?



Homework Equations



v^2= vi^2 +2a(x-xi)

The Attempt at a Solution



i suppose that the plane has a height of the radius and the initial velocity would be 0. Am I wrong? if I am, please tell me!
 
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i think only acceleration will be of gravity.
 
The equation you cite isn't relevant. Hint: centripetal acceleration.
 
nil1996 said:
i think only acceleration will be of gravity.

No. It's moving in a circle.
 
CWatters said:
No. It's moving in a circle.
I first saw at the eqn he has given and so declared as the acceleration is of gravity.
I think you are right it is centripetal acceleration.
 
oh! that's true! i totally forgot about centripetal forces!
 
You are visualizing the question wrongly I believe. The aeroplane is in the air, and is heading down towards the Earth. The pilot then pulls out of the dive - he will not go vertically up straight away, rather, he will move along a curved arc upwards. You have the radius of this arc, you have the velocity, and you have the mass. This is a straightforward formula application question.
 
if centripetal force is Fc= m(v^2/r)
then
the centripetal acceleration formula can be derived from the circular acceleration right? a=v^2 /r ,right?
 
Yes. All you need to do is divide the force by the object's mass to get it's acceleration.
 
  • #10
really? so i just do:

Fc=m (v^2/r)
Fc/m=a ? i already got confused!

they are giving me:
m=55kg
r=320m
v=230km/h

and a=v^2/r, wouldn't it be easier to just substitute the values in this formula?
 
  • #11
You don't need the mass to calculate the acceleration. You may use the formula in the last line. All the same thing really.
 
  • #12
The answer is not just the centripetal acceleration :-)
 
  • #13
they want me to find the magnitude of her acceleration, which tells me that they only want a numerical value without a direction, so if they are not asking only for centripetal acceleration then what is it!?
 
  • #14
In level flight a pilot experiences 1g.
 
  • #15
CWatters said:
The answer is not just the centripetal acceleration :-)

Why do you say that?
 
  • #16
I take it back. She feels like she is accelerating at v^2/r + g but is actually only accelerating at v^2/r.
 
  • #17
so how this affects the acceleration? would it be a=(centripetal accel.)(gravity) ??
 
  • #18
Robertoalva said:
so how this affects the acceleration? would it be a=(centripetal accel.)(gravity) ??
No, you already have the answer in the last line of your post #10.
Acceleration is completely determinable by knowing the position as a function of time. With that information, the forces that led to that pattern of movement become irrelevant.
 
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