1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Alg. 2 Help

  1. Apr 7, 2005 #1
    I have a word problem and then a finite difference problem.

    You are playing golf on the 4th hole of your favorite course. The green on this hole is circular with a radius of 20 yards. If the hole is located at the exact center of the green, what is the probablility that the ball will randomly fall within 2 feet of the center of the hole?

    finding Finite differences - nth order differences

    f(x) = 2x^2 -5x^2 -x

    I don't know how to start it and how to get the answer. Thanks for the help.
  2. jcsd
  3. Apr 7, 2005 #2
    Assuming the ball will always land on the green, just find the area of the green and the area of the 2-foot circle, then compare them (in a ratio). (Remember to keep your units consistent).
  4. Apr 7, 2005 #3
    I got 900 to 1. Is the correct or even close.
  5. Apr 7, 2005 #4


    User Avatar
    Science Advisor

    Yes. Actually, you don't even need to calculate the areas themselves to compare them. The hole has radius 2 feet and the green 60 feet- a ratio of 1 to 30. Since area depends on the square of linear distance the area will have ratio 1 to 900.
    The probability that a ball that lands randomly on the green will land in the hole is 1/900.

    As for f(x) = 2x^2 -5x^2 -x, I see a function (although I would write f(x)=
    -3x^2- x) but I see no finites differences and I certainly don't see a question!
    What is the problem?
    Last edited by a moderator: Apr 7, 2005
  6. Apr 7, 2005 #5
    The question is for the finite difference is: Show that the nth-order differences for the given function of deghree N are nonzero and constant. such as f(x) = 2x^3 - 5x^2 - x
  7. Apr 7, 2005 #6
    I am curious how you got ur 900 to 1 ratio. Would the probably also be 1 % too.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook