Algebraic form of any trygonometrical function

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The discussion centers on finding the algebraic form of x when sin x equals a value like 1/10 or sin 17 degrees. It is noted that while a decimal approximation can be easily obtained using a calculator's arcsine function, deriving an algebraic number for these sine values is likely impossible, as they would be transcendental. The sine of 17 degrees, specifically, cannot be expressed simply and involves solving complex polynomial equations, including a high-degree polynomial. The conversation emphasizes that while some sine values can be expressed algebraically, others, like sin 17 degrees, require more intricate calculations. Ultimately, the focus is on the complexity of expressing certain trigonometric values in algebraic form.
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sin x = 1/10, or any other number that can't be found in math tables - how to know what x is?
 
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What do you mean by "know"? For a great many purposes, the equation
sin x = 1/10​
is sufficient to "know" x.

If by "know" you mean a decimal approximation, well it's easy enough to get that from a calculator with the arcsine function.

If by "know" you mean finding an algebraic number* y such that
\sin \pi y = 1/10​
then I very, very strongly suspect it's impossible -- y would have to be transcendental, not algebraic.

*: An algebraic number is any number that is the root of a polynomial with integer coefficients. Numbers that can be expressed in terms of integers, +, -, *, /, and taking of roots are kinds of algebraic numbers.
 
sin 17 = x

I want to know algebraic form of x

(its 17 grades)
 
hellbike said:
sin 17 = x

I want to know algebraic form of x

(its 17 grades)
You almost surely don't want to know anything about x aside from the fact it is the sine of 17 gradians, and is approximately 0.26387305. What are you trying to do? :confused:
 
sin of 3 degrees can be written with just square roots, but sine of 17 degrees, 17 not a multiple of 3, requires solving a cubic equation, in addition to several quadratic equations.

According to Maple, sine 17 degrees is a zero of the polynomial

<br /> 281474976710656\,{x}^{48}-3377699720527872\,{x}^{46}+18999560927969280<br /> \,{x}^{44}<br /> -66568831992070144\,{x}^{42}+162828875980603392\,{x}^{40}-295364007592722432\,{x}^{38}<br /> +411985976135516160\,{x}^{36}-<br /> 452180272956309504\,{x}^{34}+396366279591591936\,{x}^{32}<br /> -280058255978266624\,{x}^{30}+160303703377575936\,{x}^{28}-74448984852135936\,{x}^{26}<br /> +28011510450094080\,{x}^{24}-8500299631165440\,{x}^{22}+2064791072931840\,{x}^{20}<br /> -397107008634880<br /> \,{x}^{18}+59570604933120\,{x}^{16}-6832518856704\,{x}^{14}+583456329728\,{x}^{12}<br /> -35782471680\,{x}^{10}+1497954816\,{x}^{8}-39625728\,{x}^{6}<br /> +579456\,{x}^{4}-3456\,{x}^{2}+1<br />
 
I assume he meant 17 gradians, which is 17 \pi / 200 radians or 15.3 degrees.

I'm pretty sure this requires solving a quintic too. (Only one quintic -- sin 72 can be expressed in terms of square roots)
 
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