Alpha Particle Elastic Collisions

AI Thread Summary
In an elastic collision between a proton and a stationary alpha particle, the conservation of momentum and kinetic energy equations are applied. The initial momentum equation simplifies to v = v1 + 4v2, while the kinetic energy equation should correctly be v^2 = v1^2 + 4v2^2. Substituting v1 into the kinetic energy equation allows for further simplification. The discussion highlights the importance of correctly applying the equations to find the fraction of kinetic energy transferred. Accurate calculations are essential for solving the problem effectively.
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Homework Statement



A proton strikes a stationary alpha particle (4He nucleus) head-on. Assuming the collision is completely elastic, what fraction of the proton’s kinetic energy is transferred to the alpha particle?

Homework Equations



Pi = Pf
Ki = Kf

The Attempt at a Solution


For Pi = Pf
mv = m1v1 + 4m2v2
cancel the m's out
v = v1 + 4v2

For Ki = Kf
1/2mv^2 = 1/2m1v1^2 + 1/2(4)m2v2^2
Cancel out the 1/2 and the m's

v^2 = v1^2 + 2v2^2

Now I'm lost.. can't substitute it into the equation, I feel like I got nowhere.

Help please.
 
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Workout said:

Homework Statement



A proton strikes a stationary alpha particle (4He nucleus) head-on. Assuming the collision is completely elastic, what fraction of the proton’s kinetic energy is transferred to the alpha particle?

Homework Equations



Pi = Pf
Ki = Kf

The Attempt at a Solution


For Pi = Pf
mv = m1v1 + 4m2v2
cancel the m's out
v = v1 + 4v2

For Ki = Kf
1/2mv^2 = 1/2m1v1^2 + 1/2(4)m2v2^2
Cancel out the 1/2 and the m's

v^2 = v1^2 + 2v2^2

Now I'm lost.. can't substitute it into the equation, I feel like I got nowhere.

Help please.
The second equation is not correct. It should be v^2 = v1^2 + 4v2^2
You can substitute v1=v-4v2 into it.


ehild
 
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