Alternating Series Test - No B_n?

FallingMan
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Homework Statement



Ʃ(-1/2)^k from 0 to infinity.

Homework Equations



Ʃ(-1)^k*B_n from 0 to infinity

where if the series converges

1. lim of B_n as n goes to infinity must = 0
2. B_n must be decreasing

The Attempt at a Solution



It doesn't look like there is a B_n in the original equation at all. Do I manipulate it algebraically somehow to extract the B_n, or is there some clever trick?

Is the B_n simply 1? If if that's the case, lim of 1 as n goes to infinity would just be one, but apparently that's not true from checking the answer (which is it does, indeed, converge).

Thanks.
 
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There quite obviously is a B_n.

Your series is \sum (-1)^n(1/2)^n.
 
HallsofIvy said:
There quite obviously is a B_n.

Your series is \sum (-1)^n(1/2)^n.



I had to wrestle with my instinct that told me I'm not allowed to do that.. I guess I stand corrected.

Thanks a lot, HallsofIvy.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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