Alternating Series Test - No B_n?

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SUMMARY

The discussion centers on the convergence of the alternating series Ʃ(-1/2)^k from 0 to infinity. Participants clarify that the series can be expressed in the form Ʃ(-1)^k*B_n, where B_n is identified as (1/2)^n. The convergence criteria are confirmed: the limit of B_n as n approaches infinity equals 0, and B_n is decreasing. The series converges, validating the application of the Alternating Series Test.

PREREQUISITES
  • Understanding of the Alternating Series Test
  • Familiarity with convergence criteria for series
  • Basic algebraic manipulation of series
  • Knowledge of limits in calculus
NEXT STEPS
  • Study the Alternating Series Test in detail
  • Learn about convergence tests for infinite series
  • Explore the concept of B_n in alternating series
  • Review limit calculations and their implications in series convergence
USEFUL FOR

Students studying calculus, particularly those focusing on series and convergence, as well as educators seeking to clarify the application of the Alternating Series Test.

FallingMan
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Homework Statement



Ʃ(-1/2)^k from 0 to infinity.

Homework Equations



Ʃ(-1)^k*B_n from 0 to infinity

where if the series converges

1. lim of B_n as n goes to infinity must = 0
2. B_n must be decreasing

The Attempt at a Solution



It doesn't look like there is a B_n in the original equation at all. Do I manipulate it algebraically somehow to extract the B_n, or is there some clever trick?

Is the B_n simply 1? If if that's the case, lim of 1 as n goes to infinity would just be one, but apparently that's not true from checking the answer (which is it does, indeed, converge).

Thanks.
 
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There quite obviously is a B_n.

Your series is \sum (-1)^n(1/2)^n.
 
HallsofIvy said:
There quite obviously is a B_n.

Your series is \sum (-1)^n(1/2)^n.



I had to wrestle with my instinct that told me I'm not allowed to do that.. I guess I stand corrected.

Thanks a lot, HallsofIvy.
 

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