Aluminium vs Copper in power lines

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Monosandalus
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Hi,

I have a question concerning the use of aluminium in power lines. I know that it's lighter than copper and thus cheaper, which is the main reason we prefer it above copper. But in fact alumunium has a lower conductivity than copper. Why is it then that one kg of aluminium can carry twice as much electricity as one kg of copper ? This seems to be contradictory to me.

Thank you :)
 
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Here's some information that should be useful in the process of considering the question objectively:

Resistivity, [itex]\rho_e, \mathrm{(\Omega \cdot m)}[/itex]:
Copper: [itex]1.68 \times 10^{-8}[/itex]
Aluminum: [itex]2.86 \times 10^{-8}[/itex]​

Conductivity, [itex]\sigma, \mathrm{(S / m)}[/itex]:
Copper: [itex]5.96 \times 10^{7}[/itex]
Aluminum: [itex]3.50 \times 10^{7}[/itex]​

Density [itex]\rho_m, \mathrm{(g/cm^3)}[/itex] [Edit: corrected copy-paste error and a typo.]
Copper: 8.96
Aluminum: 2.70
By the way, resistivity and conductivity are not independent. They are merely reciprocals. [itex]\rho_e = 1/\sigma[/itex]. Both resisitivity and conductivity are given in terms of spatial dimensions, such as unit cross-sectional area and unit length.

If [itex]A[/itex] is the cross sectional area of the conductor, [itex]\ell[/itex] is the conductor's length, then

Resistance, [itex]r = \frac{\rho_e \ell}{A}[/itex]

Conductance, [itex]G = \frac{1}{r} = \frac{\sigma A}{\ell}[/itex]

Mass, [itex]m = A \ell \rho_m[/itex]
 
Last edited:
collinsmark said:
Density ρm,(g/cm2) \rho_m, (g/cm^2)
Copper: 2.70
Aluminum: 8.96

You got those swapped. Copper is the higher density material.

BoB
 
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Think about two wires of equal length . One made from 1 kg of Copper and the other from 1 kg of Aluminium .
 
And the price of metals depends on many factors besides just their densities (their weights). Lead is not cheaper than silver because it is lighter (it isn't: lead is heavier than silver); it's cheaper because it is more abundant and easier to extract.