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**An aluminum cylinder weighs 1.01 N. When this same cylinder is completely submerged in alcohol, the volume of the displaced alcohol is 3.88 × 10-5 m3. The apparent weight of the cylinder when completely submerged is 0.778 N. What is the specific gravity of the alcohol?**

m=W/g

m(cylinder)=.10296 kg

p=m/V

.10296kg/3.88*10^5 => 2653.608kg/m^3 (avg density)

SG= 2653.608/1000=> 2.65

What did I do wrong? Thanks