Am I on the right track in solving this OpAmp problem?

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Discussion Overview

The discussion revolves around solving a problem related to operational amplifiers (OpAmps), specifically focusing on deriving the transfer function H(s) for a given circuit configuration. The scope includes homework-related mathematical reasoning and technical explanation of circuit behavior.

Discussion Character

  • Homework-related, Mathematical reasoning, Technical explanation

Main Points Raised

  • One participant presents an attempt at deriving the transfer function H(s) by simplifying the circuit with a parallel resistor and capacitor.
  • Another participant notes that for an ideal OpAmp with very high gain, the condition V+ = V- holds, indicating that V+ equals the input voltage Vin.
  • A later reply confirms the derived expression for H(s) but questions its correctness.
  • Some participants suggest that the expression could be improved by using more parentheses for clarity and standard form.

Areas of Agreement / Disagreement

Participants express uncertainty about the correctness of the derived transfer function and whether it is presented in an appropriate form. There is no consensus on the final correctness of the solution.

Contextual Notes

Participants mention the need for clarity in the mathematical expression and standard form, indicating potential limitations in the current representation of the transfer function.

Aristotle
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Homework Statement



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Homework Equations


H(s)= Vo / Vi
Ideal op amp:
V+ = V-
Vo = V-

The Attempt at a Solution


To simplify the circuit, I noticed that the 200 ohm resistor and 60 microFarad capacitor are in parallel so:
Zp = (R/sC) / [(1+sRC)/(sC)] = R / [(1+sRC)]

Seeing that the Zp is in series with the 5 ohm resistor, I went ahead and used the voltage divider in search of Vo / Vin for the transfer function:

V- = 5 / [ 5 + (200/1+s(200)(60^-6)) ] * Vo

This is the part where I stopped since I'm not quite certain on how I can relate this to Vin. Can somebody lead me to the right track?
Thank you!
 
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For an OP-AMP with very high gain (ideally infinite), it causes V+ = V-

For your configuration here, V+ = Vin
 
NascentOxygen said:
For an OP-AMP with very high gain (ideally infinite), it causes V+ = V-

For your configuration here, V+ = Vin

Okay cool, I get an answer of:

H(s) = 5 / [ 5 + (200/1+s(200)(60^-6)) ]

Does this look correct?
 
A little clumsy; it is usually written in a more standard form. I think you'd be needing more parentheses there, to make it universally correct.
 
NascentOxygen said:
A little clumsy; it is usually written in a more standard form. I think you'd be needing more parentheses there, to make it universally correct.
H(s) = 5 / [ 5 + 200 / (1+s(200)(60^-6)) ]

And yes I know I have to make it in standard form, but am just verifying
 
Last edited:

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