Am I taking the right approach? (Finding final velocity)

AI Thread Summary
The discussion revolves around solving a physics problem involving final velocity on a circular path. The initial approach suggested using the chord length formula to determine height, leading to a calculated velocity of 16.78 m/s. However, an alternative method was proposed, where the height is derived using trigonometric functions, yielding the same final answer but deemed simpler. Participants express confusion over the chord length concept and acknowledge the effectiveness of the trigonometric approach. The conversation highlights the importance of finding straightforward methods in physics problem-solving.
david13579
Messages
19
Reaction score
0
I've been given this problem http://i.imgur.com/7XtYt.png and I had no idea of how to come up with an answer since it is a circular path. The only thing that occurred to me is find the initial height using the chord length formula for a circle and then treat that chord as the hypotenuse of a right triangle. After finding "the height" that way I can then use an energy conservation approach to get the velocity and I get 16.78 m/s.

Is that a correct way of doing it?. Even if it is correct, not many people would remember the chord length formula so I doubt our professor intended for it to be solved that way. There has to be an easier way to do it.
 
Physics news on Phys.org
I find "chord length" confusing.
To find the height, I drew a horizontal line from A to the vertical line.
The distance from the center of the circle to the line is 30*cos(40) = 23.
So the height at A is 30 - 23 = 7.
I get the same final answer answer you did.
 
Delphi51 said:
I find "chord length" confusing.
To find the height, I drew a horizontal line from A to the vertical line.
The distance from the center of the circle to the line is 30*cos(40) = 23.
So the height at A is 30 - 23 = 7.
I get the same final answer answer you did.

Wow, this is more straight forward. I don't see how I see it myself.

This is what I mean by chord length . http://i.imgur.com/aNTUA.png

Thanks :)
 
Fascinating! I must attempt to derive that formula.
Funny, I never ran across it before.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top