An asteroid is orbiting around the sun at a distance of 4.2

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SUMMARY

An asteroid orbits the sun at a distance of 4.2 × 1011 meters. To determine the period of this asteroid, one must apply Kepler's 3rd Law of planetary motion. Given that Earth orbits at a distance of 1.5 × 1011 meters with a period of 3.2 × 107 seconds, the period of the asteroid can be calculated using the ratio of the distances cubed. This application of Kepler's law provides a definitive method for solving the problem.

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An asteroid is orbiting around the sun at a distance of 4.2  1011 m. If the Earth orbits around the Sun at a distance of 1.5  1011 m with a period of 3.2  107 s, what is the period of the asteroid?
 
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Hi Britty. Review Kepler's 3rd law. That should get you the answer. If you still need help, post a followup in the Homework Help section.
 

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