An atomic explanation of Newton's Third Law of Motion

In summary, the conversation discusses force at the atomic level and how it relates to Newton's third law of motion. It uses Helium atoms as an example and discusses the effects of velocity and distance on the collision between two atoms. The expert responds by correcting some misconceptions and providing a quantitative description of the collision process. They also explain the role of molecular forces and how they can cause a rebound or transfer of velocity.
  • #1
faiziqb12
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let's look at force at the atomic level to understand the Newtons third law of motion. I'll use Helium atoms as an example.

Now imagine we start with one atom HE2 stationary, and throw another atom HE1 at it.It is the velocity of HE1 that affects the motion of HE2 , because the system of these two HE2 atoms is isolated , and there is no unbalanced force on each of these . According to physics both the atoms will experience action reaction forces at the same time .

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for sake of simplicity let's consider a imaginary hollow box between the two atoms as an overlapping of their atomic forces. As soon as HE1 moves x distance inside this box , there will be a increase of y amount of velocity in HE2 and a correspoding decrease of y in the velocity of HE1 . But there is still a greater velocity in HE1 as compared to HE2 , so the process of changing of velocities will continue up to the time when both the atoms have the same amount of velocity , because after they attain the same amount of velocity they won't be able to enter tat box again .

So , is what i just explained right ?

i don't think so, because we know from our knowledge of head on elastic collisions of equal masses that when HE1 and HE2 will collide, HE2 will gain the velocity that HE1 had and HE1 will itself become stationary.

so can you please correct me , and provide me with the correct answer to understand the Newtons third law of motion ?
 
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  • #2
faiziqb12 said:
But there is still a greater velocity in HE1 as compared to HE2 , so the process of changing of velocities will continue up to the time when both the atoms have the same amount of velocity , because after they attain the same amount of velocity they won't be able to enter tat box again .

This is only half the truth. In the process of the collision, the repulsive forces between the two atoms is highest when they are closest. So they don't keep moving at the same velocity. The first continues to slow down as the second continues to accelerate. The end result is that the first atom comes to a stop and the 2nd continues on at the original velocity of the first.
 
  • #3
faiziqb12 said:
so the process of changing of velocities will continue up to the time when both the atoms have the same amount of velocity
As Drakith notes, the forces are distance dependent, not velocity dependent, so there is no reason to assume the above.

faiziqb12 said:
According to physics both the atoms will experience action reaction forces at the same time .
This is not exactly true, as changes in EM fields propagate at a finite speed. Momentum is still conserved, when you account for the momentum of the field. But Newton's 3rd in its simple form doesn't hold.
 
  • #4
Drakkith said:
In the process of the collision, the repulsive forces between the two atoms is highest when they are closest. So they don't keep moving at the same velocity.The end result is that the first atom comes to a stop and the 2nd continues on at the original velocity of the first.
could you please elaborate the process
 
  • #5
A.T. said:
As Drakith notes, the forces are distance dependent, not velocity dependent, so there is no reason to assume the above.This is not exactly true, as changes in EM fields propagate at a finite speed. Momentum is still conserved, when you account for the momentum of the field. But Newton's 3rd in its simple form doesn't hold.

thats fine but the distance itself depends on the velocity .
doesnt it ?
 
  • #6
faiziqb12 said:
thats fine but the distance itself depends on the velocity .
doesnt it ?
You need a quantitative description, not vague arguments.
 
  • #7
A.T. said:
You need a quantitative description, not vague arguments.
i am sorry but i didnt get you
 
  • #8
A.T. said:
You need a quantitative description, not vague arguments.

basically , it appears like when a moving atom reaches another stationary atom they must both move together because the molecular force between them will join them together . So , if my reasoning is right an atom will never rebound back or give its velocity to the stationary atom , but rather take the stationary atom with itself.

well that isn't quite right ?
so could you please correct me ?

i really need help with this
 
  • #9
faiziqb12 said:
could you please elaborate the process

Imagine two balls with springs attached undergo a collision, with the first coming from the left and impacting the second, which is stationary. During the collision the springs are compressed as the balls approach each other. When the balls are at their closest, the springs have maximum compression and exert the maximum amount of force. This accelerates the two balls away from each other. As they begin to get further apart, the force exerted by the springs drops off until it reaches zero. At this point the collision process is over and the 2nd ball is now moving at the same speed and in the same direction as the first ball was prior to the collision. The first ball is now stationary.
 
  • #10
Drakkith said:
Imagine two balls with springs attached undergo a collision, with the first coming from the left and impacting the second, which is stationary. During the collision the springs are compressed as the balls approach each other. When the balls are at their closest, the springs have maximum compression and exert the maximum amount of force. This accelerates the two balls away from each other. As they begin to get further apart, the force exerted by the springs drops off until it reaches zero. At this point the collision process is over and the 2nd ball is now moving at the same speed and in the same direction as the first ball was prior to the collision. The first ball is now stationary.

thanks for the answer
my question is somewhat resolved ..
it looks like velocity of the moving object is is its ability to break the atomic force and reach nearer the atom , so if we have such a large velocity of the moving object that it can coincide with the nucleus and still have some velocity remaining , then how would you explain that
 
  • #11
faiziqb12 said:
thanks for the answer
my question is somewhat resolved ..
it looks like velocity of the moving object is is its ability to break the atomic force and reach nearer the atom , so if we have such a large velocity of the moving object that it can coincide with the nucleus and still have some velocity remaining , then how would you explain that

At that point you'd have to get into quantum electrodynamics and/or quantum chromodynamics to explain the interaction between the two atoms since the forces involved and the interactions of the atoms no longer behave classically.
 
  • #12
Drakkith said:
At that point you'd have to get into quantum electrodynamics and/or quantum chromodynamics to explain the interaction between the two atoms since the forces involved and the interactions of the atoms no longer behave classically.
why specifically can't the phenomenon be explained by quantum electrodynamics..?
and could you also give the links where i could find about , how to explain this phenomenon by quantum electrons or rather please explain yourself
 
  • #13
faiziqb12 said:
why specifically can't the phenomenon be explained by quantum electrodynamics..?
and could you also give the links where i could find about , how to explain this phenomenon by quantum electrons or rather please explain yourself

I cannot, as I am not familiar enough with either QED or QCD.
 
  • #14
Drakkith said:
I cannot, as I am not familiar enough with either QED or QCD.
sorry , i meant why specifically can't the phenomenon be explained without quantum electrodynamics or chromodynamics either..?
well , i have understood the "i don't know" form you , so this reply is just a correction of what i said
 
  • #15
faiziqb12 said:
sorry , i meant why specifically can't the phenomenon be explained without quantum electrodynamics or chromodynamics either..?

Because once you get down to the level of where atoms are colliding at high enough velocities to overcome their coulomb repulsion, classical mechanics can no longer describe the interaction. You have to take into account three different forces (EM, weak force, and strong force) along with several quantum mechanical phenomenon which don't even exist in classical mechanics. I'm sorry but I don't really know much more than that.
 
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  • #16
Drakkith said:
Because once you get down to the level of where atoms are colliding at high enough velocities to overcome their coulomb repulsion, classical mechanics can no longer describe the interaction. You have to take into account three different forces (EM, weak force, and strong force) along with several quantum mechanical phenomenon which don't even exist in classical mechanics. I'm sorry but I don't really know much more than that.
thanks for that ..
well , exchanging even a single drop of knowledge , means you have changed the life of another person , and then admitting that is even a more beautiful deed , people like you are very rare .
anyway , thanks !
 
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  • #17
Even with two He atoms we can make this as complicated as we want ;-).
Lets assume that the collision takes place at sufficiently low energy so that both He stay in the ground state. It is convenient in QM to think in terms of energy and momentum, not force. Newton's third law is a statement of momentum conservation. The total momentum, the sum over electrons and nuclei is constant in time. As He1 slams into He2, the electrons interact via the quasistatic e-e Coulomb force and the Pauli principle. The electrons of He1 slow down and the electrons of He2 accelerate. Via the quasistatic Coulomb e-n force this leads to deceleration of the He1 nucleus and acceleration of the He2 nucleus. If the collision is head-on, He1 will transfer all momentum to He2, as in Newton's cradle. During the collision the atoms deform through virtual excited states in QM language. As long as you don't care how long the collision takes, you don't have to think about this.
Note that He can form a very weakly bound vanderWaals dimer ( https://en.wikipedia.org/wiki/Helium_dimer ), so at very low energy the two atoms will stick together ! There are subtle effects involving rotation and vibration states of this dimer leading to emission of infrared light.
If there is enough kinetic energy, one or both atoms may be excited, if conservation of momentum and energy allows. Then things get really interesting, since a chemical bond between the atoms may form resulting in an excimer. Excimer lasers exploit this phenomenon. Photons will be emitted and these must be considered in the sum of all momenta. See https://en.wikipedia.org/wiki/Helium_dimer#Excimers .
 
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  • #18
my2cts said:
Note that He can form a very weakly bound vanderWaals dimer ( https://en.wikipedia.org/wiki/Helium_dimer ), so at very low energy the two atoms will stick together ! There are subtle effects involving rotation and vibration states of this dimer leading to emission of infrared light.
If there is enough kinetic energy, one or both atoms may be excited, if conservation of momentum and energy allows. Then things get really interesting, since a chemical bond between the atoms may form resulting in an excimer. Excimer lasers exploit this phenomenon. Photons will be emitted and these must be considered in the sum of all momenta. See https://en.wikipedia.org/wiki/Helium_dimer#Excimers .

well , this question may be a bit awkward , but will i read about helium dimer in high school , currently i am in 9th class .. well , i haven't even read the pauli exclusion principle yet that you mentioned
so , is a graduate matter of study or high school ?
 
  • #19
Quick point of order here: did you move past your original question? Are you interested in Newton's laws or atomic physics?

If you want to explore Newton's laws on an atomic (molecular) model, you've gone too far into atomic physics. If you want to explore atomic physics, Newton's laws don'T much apply.
 
  • #20
russ_watters said:
Quick point of order here: did you move past your original question? Are you interested in Newton's laws or atomic physics?

If you want to explore Newton's laws on an atomic (molecular) model, you've gone too far into atomic physics. If you want to explore atomic physics, Newton's laws don'T much apply.

thanks , maybe that could be considered as an compliment
 
  • #21
To bounce off of Russ's post, when we discuss things using classical mechanics, which is built off of Newton's laws, we usually don't talk about things at either the atomic scale or the intergalactic scale (the very small and the very large). At these scales Newton's laws start to become inaccurate and we have to use quantum physics and/or general relativity, both of which are MUCH more complicated and less intuitive than classical mechanics.
 
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1. What is Newton's Third Law of Motion?

Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. This means that when an object exerts a force on another object, the second object will exert an equal and opposite force back on the first object.

2. How does this law relate to atoms?

Atoms are the building blocks of matter and everything in the universe. They are constantly in motion and interact with each other through forces. When two atoms come into contact, they exert equal and opposite forces on each other, in accordance with Newton's Third Law.

3. Can you give an example of an atomic explanation of this law?

One example is when two atoms collide. The atoms will exert equal and opposite forces on each other, leading to a change in their velocities and directions of motion. This can be observed in the collision of gas particles in a container, where the particles bounce off each other due to the forces they exert on each other.

4. Does this law only apply to interactions between atoms of the same element?

No, Newton's Third Law applies to all interactions between objects, regardless of their composition. This means that the forces between different types of atoms, such as between hydrogen and oxygen atoms in water molecules, also follow this law.

5. How does understanding this law at the atomic level benefit us?

Understanding this law at the atomic level allows us to better explain and predict the behavior of matter and objects in the physical world. It also helps in the development of new technologies and advancements in fields such as chemistry, physics, and engineering.

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