An inexact differential equation

Kaguro
Messages
221
Reaction score
57
Homework Statement
Solve the following differential equation:
(siny*cosy +xcos^2(y))dx + xdy=0
Relevant Equations
##\frac{\partial M}{\partial y} \neq \frac{\partial N}{\partial x} ##
So equation is inexact.
Here, M = ##siny*cosy +xcos^{2}y ## and N = x
## M_y = (1/2)cos(2y) -xsin(2y)##
and ##N_x = 1##

Theorems:
If R = ## \frac{1}{N} (M_y - N_x) = f(x), then I.F. = e^{ \int f(x) dx} ##
If R = ## \frac{1}{M} (N_x - M_y) = g(y), then I.F. = e^{ \int g(x) dx} ##

Neither is holding true.
What should I do?

I tried writing N = ## x(sin^{2}y + cos^{2}y)## thinking it may help, but it didn't.
 
Physics news on Phys.org
Try to divide by ##\cos^2(y)## and use ##\dfrac{d}{dy}\tan(y)=\dfrac{1}{\cos^2(y)}## and substitute ##u = \tan(y)##.
 
  • Like
Likes ehild
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top