# Analysis Question 1

1. Apr 28, 2009

### Janez25

1. The problem statement, all variables and given/known data
For all real numbers a and b, define g(x) = 3x² if x≤1, a+bx if x>1. For what values of a and b is g differentiable at x=1?

2. Relevant equations

3. The attempt at a solution
g(x) is continuous: lim as x→1- [f(x)] = 1; lim as x→1+ [f(x)] = a+b
g(x) is differentiable: g'(x) = lim as x→1- of [(g(x)-g(1))/x-1] = 6 and g'(x) = lim as x→1+ [(g(x)-g(1))/x-1]=lim as x→1+ (b) = 0 {I think the limit from the right is correct}
I believe a=6, and I am not sure what b equals.
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Apr 29, 2009

### snipez90

Where did f come from? For the first part, lim as x -> 1- [g(x)] =/= 1, so a + b should equal a number that is not 1 in the resulting equation. Just as for your second analysis problem, think about what g'(x) should be for x < 1 and what it should be for x > 1.

Last edited: Apr 29, 2009
3. Apr 29, 2009

### HallsofIvy

Staff Emeritus
No, the limit from the right is NOT correct. For x> 1, g(x)= a+ bx and the derivative of a linear function is just its slope, b. Since the limit from the left is 6, you have b= 6, together with your previous equation, a+ b= 1.

4. Apr 29, 2009

### Janez25

Ok, I have it now. Thanks!